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3 years ago

What is the length of the longest side of a triangle that has the vertices (-5, 6), (-5, -2), and (1, -2)?

Mathematics

1 answer:

pshichka [43]3 years ago

6 0

Check the picture below.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -5 &,& 6~) 
% (c,d)
&&(~ 1 &,& -2~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[1-6]^2+[-2-(-5)]^2}\implies d=\sqrt{(1-6)^2+(-2+5)^2}
\\\\\\
d=\sqrt{(-5)^2+3^2}\implies d=\sqrt{25+9}\implies d=\sqrt{34}$

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mezya [45]

Answer:

The probability of Javier volunteers for less than three a month is 25%

Step-by-step explanation:

According to the questions,

The probability of Javier to attend exactly 5 events :-

P ( x = 5 ) = 25% = $\frac{1}{4}$

The probability of Javier to attend exactly 4 events :-

P ( x = 4 ) = $\frac{1}{4}$

The probability of Javier to attend exactly 3 events :-

P ( x = 3 ) = $\frac{1}{4}$

The probability of Javier to attend exactly 2 events :-

P ( x = 2 ) = $\frac{3}{20}$

The probability of Javier to attend exactly 1 events :-

P ( x = 1 ) = $\frac{1}{20}$

The probability of Javier to attend no events :-

P ( x = 0 ) = $\frac{1}{20}$

Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).

P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )

P ( x < 3 ) = $\frac{1}{20} + \frac{1}{20} + \frac{3}{20}$ $= \frac{1 + 1 + 3}{20}$ = $\frac{5}{20}$ = $\frac{1}{4}$ = 0.25 = 25 %.

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alexandr402 [8]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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