Using the t-distribution, it is found that the 95% confidence interval for the mean number of people the houses were shown is (20.1, 27.9).
We have the <u>standard deviation for the sample</u>, hence the t-distribution is used to build the confidence interval. Important information are given by:
- Sample mean of
. - Sample standard deviation of
. - Sample size of
The confidence interval is:
In which t is the critical value for a <u>95% confidence interval with 23 - 1 = 22 df</u>, thus, looking at a calculator or at the t-table, it is found that t = 2.0739.
Then:
The 95% confidence interval for the mean number of people the houses were shown is (20.1, 27.9).
A similar problem is given at brainly.com/question/15180581
Answer: Perpendicular Bisector
Answer:
vgkf çµr nm 5hr 6tqy7gu8hibyg7tf6r5d4es3
Step-by-step explanation:
Answer:
Width = 40ft
Step-by-step explanation:
Area of a rectangle = Length x Width
=> 1600 = 40 x W
=> 1600 = 40W
=> 1600/40 = 40W/40
=> 40 = W
So, the width is 40 ft
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
