Add 2p² to each side of the equation. Then you have

2p² + 16p + 24 = 0 .

Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by 2 . Then you have:

p² + 8p + 12 = 0 .

Now you have a nice, comfortable, familiar-looking quadratic equation.
You can either factor the left side into (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.

That's how to solve it, and find its two solutions.

8 0

3 years ago

Find f(-2) for the function:<br><br> f(x)= 3x^2-1, x<1<br> x+2, x> 1

azamat

F(x) = 3x² - 1
f(-2) = 3(-2)² - 1
f(-2) = 3(4) - 1
f(-2) = 12 - 1
f(-2) = 11

f(x) = x < 1
f(-2) = -2 < 1

f(x) = x + 2
f(-2) = -2 + 2
f(-2) = 0

f(x) = x > 1
f(-2) = -2 > 1
f(-2) = -2 < 1

8 0

3 years ago