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Vilka [71]
3 years ago
7

How do I solve this?

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
6 0

Answer

First of all, we need to identify the type of equation this is...

Since we are solving two at a go, it means it's a simultaneous equation.

Now, we need to solve them differently.

Taking the first one which says...

3x -y = -2

Then we say

When x is 0, y =?

So in the equation above , we replace x with 0

Meaning- 3x-y = -2

3(0) -y= -2

0 -y= 2

-y =-2

Y =2

Also, when y =0.

3x- 0 =-2

3x=-2

X=-2/3.

Also for the other equation

2x+ y =-3

When x= 0 in the above equation

2(0) + y= -3

0 +y=-3

Y=-3

When y = 0

2x+ 0= -3

2x = -3

X=-3/2

The above is what well plot on the graph.

t

Step-by-step explanation:

AleksAgata [21]3 years ago
4 0

Answer:

x = -1

y = -1

Step-by-step explanation:

3x - y = -2

2x + y = -3

Multiply equation 1 by 2 and equation 2 by 3

We have

2x3x - 2xy = 2x-2

3x2x + 3xy = -3x3

Equation 1 6x - 2y =-4

Equation 2 6x + 3y = -9

Subtract equation 2 from 1

We have -5y = 5

Divide both sides by -5

y = 5/-5 = -1

Now Substitute y = -1 into any of the equations to get x

Using equation 1 , we have

3x - (-1) = -2

3x +1 = -2

Collect like terms

3x = -2 -1

3x = -3

Divide both sides by 3

x = -3/3 = -1

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