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sashaice [31]
3 years ago
12

What is the average rate of change from x = 0 to x = −2?

Mathematics
1 answer:
yarga [219]3 years ago
8 0
-1
................... ..
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BRAINIST &amp; 20 POINTS <br><br><br> *random answers will be reported*
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Answer:

6-1

Step-by-step explanation:

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At a bargain store, Tanya bought 3 items that each cost the same amount. Tony bought 4 items that each cost the same amount, but
babunello [35]
If x is the amount that Tanya paid for each item, then Tony's items would be x-2.25. So:
3x=4(x-2.25)

3x=4x-9
x=9
x-2.25=6.75
Tanya spent $9 on each item; Tony spent $6.75 on each of his items
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iVinArrow [24]
The next term in the sequence is double the previous term . so it would be the 3rd option (48,96,192)
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3 years ago
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610 divided by 20 without a decimal
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Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938&#10;

Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
3 years ago
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