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Sedaia [141]
3 years ago
10

What is the sum of 3/4 and 18/19

Mathematics
2 answers:
nadezda [96]3 years ago
4 0
If you add them togeter just like making your t-charts

Ex1

3/4 18/19. List the factors of 19 and 4 if you subtract you have to find the GCF that will be on the bootom then do it to the top
Karo-lina-s [1.5K]3 years ago
4 0
3/4 + 18/19
(57+72) / 76
<span>129 / 76</span>
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I didnt put the answer choices because ppl be putting random stuff
lesya692 [45]
I’m pretty sure the answer is 127.48 ,but I could be wrong.
5 0
3 years ago
The graph represents the function f(x) = x2 + 3x + 2. If g(x) is the reflection of f(x) across the x-axis, g(x) = . (Write the f
Tanya [424]

Answer:

g(x) = - (x² + 3x + 2) = - x² - 3x - 2

Step-by-step explanation:

The graph represents the function f(x) = x² + 3x + 2.

Now, g(x) is the function which is obtained by reflecting f(x) across the x-axis.

While a graph of a function reflects across x-axis then its y-values will change sign for a fixed value of x.  

Therefore, the function g(x) will be given by  

g(x) = - (x² + 3x + 2) = - x² - 3x - 2 (Answer)

7 0
3 years ago
X / 12 equals 27 / 33 ​
Alexxandr [17]
What is your question?
5 0
3 years ago
The work of a student to solve a set of equations is shown below: Equation 1: x + 2y = 10 Equation 2: 2x + 5y = 15 Step 1: −2(x
DIA [1.3K]
 −2x − 4y = −10 2x + 5y = 15 
6 0
3 years ago
Read 2 more answers
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
IgorLugansk [536]

Answer:

Do no reject null hypothesis.  

Conclusion:

there is no sufficient statistical evidence at 0.025 level of significance to support the claim.

Step-by-step explanation:

Given that;

mean x" = 5.4

standard deviation σ = 0.7  

n = 6

Null hypothesis H₀ : μ = 5.0  

Alternative hypothesis H₁ : μ > 5.0    

∝ = 0.025    

now,

t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4

degree of freedom df = n-1 = 6 - 1 = 5

T critical = 2.571

Therefore; t < T critical,

Do no reject null hypothesis.  

Conclusion:

there is no sufficient statistical evidence at 0.025 level of significance to support the claim.

3 0
3 years ago
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