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sp2606 [1]
3 years ago
12

Need help with this

Mathematics
1 answer:
jeka57 [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Jamie is correct.

two angles are equal in an isosceles triangle.

let the angles be x,x,y

if she knows x

then y=180-(x+x)=180-2x

so she can find y

similarly if she knows y then she can calculate x.

You might be interested in
Value of 4g + 5h when g=1 h=4
GaryK [48]
So pretty much, 4g is 4 times g right? taking this into consideration, replace g with x1 and h with x4. Then you get 4 x 1 + 5 x 4. Since you're always supposed to multiply and then add (left to right), it would equal 4 + 20 which is 24. Good luck on your test.
8 0
3 years ago
Read 2 more answers
Anyone mind helping me ?
storchak [24]

Answer:

<GOJ

Step-by-step explanation:

O is the center of the circle

So central angle is <GOJ

3 0
3 years ago
Please help!!! It is very hard!!!!!!!!!!!¡!!!!!!!!!!!!!!!!!!
cupoosta [38]
A- 5.3 cm
B- 17.8m
C-9.7 in
D-12 cm
E- 8.3ft
F-25.5m
7 0
3 years ago
A man is in a boat 2 miles from the nearest point on the coast. He is to go to point Q, located 3 miles down the coast and 1 mil
mafiozo [28]

Answer:

The answer is "0.45385".

Step-by-step explanation:

The time is taken to reach the coast = \frac{\sqrt{(2^2 + x^2)}}{4}

The  time is taken to reach Q after reaching the coast = \frac{\sqrt{(1 + (3-x)^2)}}{4}

Total time, T= \frac{\sqrt{(1 + (3-x)^2)}}{4}+  \frac{\sqrt{(1 + (3-x)^2)}}{4}

This has to be minimum,

\to \frac{dt}{dx} = 0

\to \frac{\sqrt{(2^2 + x^2)}}{2} + \frac{\sqrt{1 + (3-x)^2}}{3}\\\\ \frac{x}{4}\sqrt{(4+x^2)} + \frac{(x-3)}{(4\sqrt{(x^2-6x+10)}} = 0\\\\\frac{x^2}{16} \times (4+x^2) = \frac{(x-3)^2}{16  \times (x^2-6x+10)}\\\\x^2(4+x^2) = \frac{(x-3)^2}{(x^2-6x+10)}\\\\4x^2+x^4 = \frac{ x^2+9-6x}{(x^2-6x+10)}\\\\ 4x^2+x^4(x^2-6x+10) = x^2+9-6x\\\\4x^4-24x^3+40x^2+x^6-6x^5+10x^4= x^2+9-6x\\\\x^6-6x^5+ 14x^4-24x^3+39x^2+6x-9=0\\\\

x=0.45385

6 0
3 years ago
Need help with figuring out this zingoes problem asap, willing to give brainliest!
muminat

Answer:

The yellow trapezoid, blue rectangle, and whatever that purple thing is are zingoes

Step-by-step explanation:

As far as I can tell, all the correct examples are

1) Symmetrical

2) Have a line splitting them symmetrically and does not go above or below the shape (Does that make sense?)

The wrong examples don't have any of the characteristics told above. For example, the square would be wrong because it doesn't even have a line

(P.S- This isn't my picture, just found it on the web. Shout out to whoever owns this)

7 0
3 years ago
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