Answer:
jh
Step-by-step explanation:
hh6bynnynyb7j7jbtvrf2xecrvubuvrcryvhbjbibxidh ixh idh!7sgzuefzuwz
Base in your question that ask to find the Taylor series for function f(x) at a given value of A. And assume that F has a power series expansion. So to solve this you must first derive its function in to a standard series for taylor. Then after that you will came up with a solution of <span>Ts</span>=<span>c0</span><span><span>(x−a<span>)^0/</span></span><span>0! </span></span>+ <span>c1</span><span><span>(x−a<span>)^1/ </span></span><span>1! </span></span>+ <span>c2</span><span><span>(x−a<span>)^2/</span></span><span>2!</span></span>+<span>c3</span><span><span>(x−a<span>)^3/</span></span><span>3!</span></span>
Answer:
D
Step-by-step explanation:
10/7 = 1.4285
9/y = 1.4285
Multiply both sides by y.
9 = 1.4285y
Divide both sides by y.
6.3 = y
Use a calculator and get 4.72
Answer:
C
Step-by-step explanation:
we are just multiplying 6.1x0.12 it gives us 0.732 simple
