In constructing a frequency table, first you'll need to arrange your data from lowest to highest and solve for the following: range, class width, and class size.
Range: Highest Value - Lowest Value in the data set.
= 18 - 0 = 0
Class Width: Square root of the total number of data. In the data set, we have 14 numbers. This is the number of classes.
= sqrt (14) = 3.7 or 4
Class Size: Range divided by Class Width.
=18/4 = 4.5 or 5. There should be five numbers inside each class.
The Frequency Table is below.
Eagles | Frequency
0-4 4
5-9 5
10-14 3
15-19 2
6) it’s -11a^2b^(because they have the same letters plus both of them have squares and if there isn’t any number in the on the other side it means that it is 1)
7)1mn(subtract and then put the sign of the bigger number)
9)-50xy^2(addition)
10)-49ac^d(subtract and put the sign of the bigger number)
11) 7y + 6z(arrange them first and then add and subtract.)
(Hope this helps)
Answer:
21
Step-by-step explanation:
7x3=21
21/3=7
you just have to use inverse operations
(: hope this helps
<h2>
Question:</h2>
Evaluate using a suitable identity: (997)³
<h2>
Answer:</h2>
991026973
<h2>
Step-by-step explanation:</h2>
Given:
(997)³
To solve this using an appropriate identity;
i. <em>Rewrite by splitting the value in bracket (997) into a difference of two numbers. i.e</em>
(997)³ = (1000 - 3)³
<em>ii. Use the appropriate identity</em>
Since the split from (i) above gave a cube of the difference of two numbers, we can apply the following identity for finding the cube of the difference of two numbers;
(a - b)³ = a³ - b³ - 3ab(a - b)
In this case;
a = 1000
b = 3
<em>(iii) Substitute the values of a and b into the identity equation and solve;</em>
(1000 - 3)³ = 1000³ - 3³ - 3(1000)(3)(1000 - 3)
(1000 - 3)³ = 1000000000 - 27 - 9000(997)
(1000 - 3)³ = 1000000000 - 27 - 8973000
(1000 - 3)³ = 991026973
Therefore,
(997)³ = 991026973