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AleksAgata [21]
3 years ago
8

A polynomial function P(x) with rational coefficients has the given roots. Find two additional roots of P(x)=0.

Mathematics
2 answers:
timofeeve [1]3 years ago
4 0

Answer:

Step-by-step explanation:

If a polynomial function P(x) with rational coefficients has a root z. the so is the complex conjugate of z is a root. (In order to see that, take the complex conjugates of the equation P(x)=0, and note that complex conjugates of rational numbers equal to itself.)

Therefore the complex conjugates of the given roots i and 7+8i , are -i and 7-8i is the required answer.

castortr0y [4]3 years ago
3 0

Answer:

B

Step-by-step explanation:


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I need help don't just give a random answer for the points pz got to get done quickly
saveliy_v [14]

Answer:

$140

Step-by-step explanation:

1 meal --- $15

8 meals --- $15 × 8 = $120

Total = $120 + $20

        = $140

6 0
3 years ago
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What is the volume, in cubic m, of a cube with an edge length of 11m?
rewona [7]

the volume of cube with edge length 11 m is Volume = 1331m^3 .

<u>Step-by-step explanation:</u>

Here  we have a side length of a cube as 11 m . We need to find the volume of cube . Let's find out:

We know that every side of a cube is identical and equal . And volume of cube is given by formula :

⇒ Volume = (side)^3   ...........(1)

According to question we have following parameters as

side = 11m

Putting this in (1)

⇒ Volume = (11m)^3

⇒ Volume = 11(11)(11)m^3

⇒ Volume = (121)(11)m^3

⇒ Volume = 1331m^3

Therefore , the volume of cube with edge length 11 m is Volume = 1331m^3 .

3 0
3 years ago
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A closed box with a square base is to have a volume of 171 comma 500 cm cubed. The material for the top and bottom of the box co
Zepler [3.9K]

Answer:

C(x)=\dfrac{20x^3+1715000}{x}\\$Minimum cost, C(35)=\$29,400

The dimensions that will lead to minimum cost of the box are a base length of 35 cm and a height of 140 cm.

Step-by-step explanation:

Volume of the Square-Based box=171,500 cubic cm

Let the length of a side of the base=x cm

Volume =x^2h

x^2h=171,500\\h=\dfrac{171500}{x^2}

The material for the top and bottom of the box costs ​$10.00 per square​ centimeter.

Surface Area of the Top and Bottom =2x^2

Therefore, Cost  of the Top and Bottom =\$10X2x^2=20x^2

The material for the sides costs ​$2.50 per square centimeter.

Surface Area of the Sides=4xh

Cost of the sides=$2.50 X 4xh =10xh

\text{Substitute h}$=\dfrac{171500}{x^2} $into 10xh\\Cost of the sides=10x(\dfrac{171500}{x^2})=\dfrac{1715000}{x}

Therefore, total Cost of the box

= 20x^2+\dfrac{1715000}{x}\\C(x)=\dfrac{20x^3+1715000}{x}

To find the minimum total cost, we solve for the critical points of C(x). This is obtained by equating its derivative to zero and solving for x.

C'(x)=\dfrac{40x^3-1715000}{x^2}\\\dfrac{40x^3-1715000}{x^2}=0\\40x^3-1715000=0\\40x^3=1715000\\x^3=1715000\div 40\\x^3=42875\\x=\sqrt[3]{42875}=35

Recall that:

h=\dfrac{171500}{x^2}\\Therefore:\\h=\dfrac{171500}{35^2}=140cm

The dimensions that will lead to minimum costs are base length of 35cm and height of 140cm.

Therefore, the minimum total cost, at x=35cm

C(35)=\dfrac{20(35)^3+1715000}{35}=\$29,400

8 0
3 years ago
Find all critical numbers of the function <img src="https://tex.z-dn.net/?f=g%28x%29%3Dx%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7D-2x%5E%
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g'(x) = \dfrac{3\sqrt x - 2}{4 x^{\frac34}}

The critical points of g occur where g' is zero or undefined.

We have

g'(x) = 0 \implies 3\sqrt x - 2 = 0 \implies \sqrt x = \dfrac23 \implies \boxed{x = \dfrac49}

and the derivative is undefined for

\dfrac1{g'(x)} = 0 \implies 4x^{\frac34} = 0 \implies \boxed{x=0}

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What is 10.5 divided by 1.5
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Answer:

The answer would be 7.

Step-by-step explanation:

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