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lisabon 2012 [21]
3 years ago
5

I need help don't just give a random answer for the points pz got to get done quickly

Mathematics
2 answers:
saveliy_v [14]3 years ago
6 0

Answer:

$140

Step-by-step explanation:

1 meal --- $15

8 meals --- $15 × 8 = $120

Total = $120 + $20

        = $140

Alborosie3 years ago
3 0

Answer:

140

Step-by-step explanation:

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For the diagram at right, write and solve an equation to find x
Tomtit [17]

Answer:

x = 24

Step-by-step explanation:

The formula for determining the sum of interior angles is:

(n-2) * 180

4 * 180 = 720

Therefore to determine an equation for x, we must add up all the interior angle equations and set them equal to 720.

(2x+3) +(3x+12) + (7x+14) + (9x+2) + (4x+8) + (3x+9) = 720\\28x + 48 = 720\\28x = 672\\x = 24

The equation and answer above shows how to find x, which equals 24.

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2 years ago
Salvador inherited $20,000 and he plans to invest it into a savings account that earns 6% interest compounded annually. Assuming
Alex787 [66]

Answer:

Step-by-step explanation:

initial value(1+ percent of interest in decimal form)^(years)

20,000(1.06)^10

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7 0
3 years ago
Line j is parallel to line k. Find the m
Rufina [12.5K]

Answer:

- 8.14 = m = slope

Step-by-step explanation:

We know from the diagram that  8x-7  + 5x+18  = 180    so x = 13

  so 8x -7  =  97

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8 0
2 years ago
Evaluate the double integral. 2y2 dA, D is the triangular region with vertices (0, 1), (1, 2), (4, 1) D
zubka84 [21]

Answer:

\mathbf{\iint _D y^2 dA=  \dfrac{22}{3}}

Step-by-step explanation:

From the image attached below;

We need to calculate the limits of x and y to find the double integral

We will notice that y varies from 1 to 2

The line equation for (0,1),(1,2) is:

y-1 = \dfrac{2-1}{1-0}(x-0)

y - 1 = x

The line equtaion for (1,2),(4,1) is:

y-2 = \dfrac{1-2}{4-1}(x-1) \\ \\ y-2 = -\dfrac{1}{3}(x-1)

-3(y-2) = (x -1)

-3y + 6 = x - 1

-x = 3y - 6 - 1

-x = 3y  - 7

x = -3y + 7

This implies that x varies from y - 1 to -3y + 7

Now, the region D = {(x,y) | 1 ≤ y ≤ 2, y - 1 ≤ x ≤ -3y + 7}

The double integral can now be calculated as:

\iint _D y^2 dA= \int ^2_1 \int ^{-3y +7}_{y-1} \ 2y ^2  \ dx \ dy

\iint _D y^2 dA= \int ^2_1 \bigg[ 2xy ^2 \bigg]^{-3y+7}_{y-1}  \ dy

\iint _D y^2 dA= \int ^2_1 \bigg[2(-3y+7)y^2-2(y-1)y^2 \bigg ]  \ dy

\iint _D y^2 dA= \int ^2_1 \bigg[-6y^3 +14y^2 -2y^3 +2y^2 \bigg ]  \ dy

\iint _D y^2 dA= \int ^2_1 \bigg[-8y^3 +16y^2  \bigg ]  \ dy

\iint _D y^2 dA=  \bigg[-8(\dfrac{y^4}{4})  +16(\dfrac{y^3}{3})\bigg ] ^2_1

\iint _D y^2 dA=  \bigg[-8(\dfrac{16}{4}-\dfrac{1}{4})  +16(\dfrac{8}{3}-\dfrac{1}{3})\bigg ]

\iint _D y^2 dA=  \bigg[-8(\dfrac{15}{4})  +16(\dfrac{7}{3})\bigg ]

\iint _D y^2 dA=  -30 + \dfrac{112}{3}

\iint _D y^2 dA=  \dfrac{-90+112}{3}

\mathbf{\iint _D y^2 dA=  \dfrac{22}{3}}

4 0
3 years ago
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