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3 years ago

What is the volume, in cubic m, of a cube with an edge length of 11m?

Mathematics

2 answers:

Ainat [17]3 years ago

5 0

The volume of the cube is 1331 m³

Explanation:

Given:

side of the cube, a = 11m

Volume of the cube, v = ?

we know:

Volume of the cube = (a)³

V = (11m)³

V = 1331 m³

Therefore, the volume of the cube is 1331 m³

rewona [7]3 years ago

3 0

the volume of cube with edge length 11 m is $Volume = 1331m^3$ .

Step-by-step explanation:

Here we have a side length of a cube as 11 m . We need to find the volume of cube . Let's find out:

We know that every side of a cube is identical and equal . And volume of cube is given by formula :

⇒ $Volume = (side)^3$ ...........(1)

According to question we have following parameters as

$side = 11m$

Putting this in (1)

⇒ $Volume = (11m)^3$

⇒ $Volume = 11(11)(11)m^3$

⇒ $Volume = (121)(11)m^3$

⇒ $Volume = 1331m^3$

Therefore , the volume of cube with edge length 11 m is $Volume = 1331m^3$ .

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3 years ago

How to do this step by step?

serg [7]

The answer is 27.6
angle version of the law of cosines:

cos(C) = (a^2 + b^2 − c^2)/2ab

cos(A) = (b^2 + c^2 − a^2)/2bc

cos(B) = (c^2 + a^2 − b^2)/2ca

cos A = (b^2 + c^2 − a^2) / 2bc
cos A = (10^2+20^2-14^2)/200
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cos A = (304)/200
cos A = (1.52)
A = cos^-1(1.52) = 40.54 degrees

cos B = (c^2+a^2-b^2)/2ca
cos B = (20^2+14^2-10^2)/280
cos B = (400+196-100)/280
cos B = (496)/280
cos B ≈ 1.77
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we have two methods left to find the measure of angle C:
method 1 :
cos C = (a^2+b^2-c^2)/2ab
cos C = (14^2+10^2-20^2)/140
cos C = (196+100-400)/140
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cos C ≈ -0.74

C = cos^-1(-0.74) = 111.8 degrees

method 2: 40.54+27.66 = 68.2
180-68.2=111.8

The measure of angle A: 40.54
The measure of angle B: 27.66
The measure of angle C: 111.8

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