Answer:
A) attached below
B) 0.61
C) 0.47
Step-by-step explanation:
Given data:
Total number of lizards infected = 38
Of the 15 species B lizards 40% survived
For specie C one more survived than died
Out of the 24 lizards that died 1/3 were species A
<u>A) contingency table </u>
attached below
<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>
P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61
<u>C) determine the probability that specie C lizard did not study </u>
P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47
The correct answer is (2g2 - 3) • (4g + 5)
Answer:
5 : -1.5
10: -4
y = 1 -.5x
noticed the pattern of subtracting .5 .... then plugged in x = 4
and saw that -2 had to be combined with "1" to end up with a "-1"
Step-by-step explanation:
12 units, hmm.. I think your answer is correct.
True!
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