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rosijanka [135]
2 years ago
12

❗️ILL GIVE BRAINLIEST❗️

Mathematics
1 answer:
Gekata [30.6K]2 years ago
8 0

1. 120 im not sure

Step-by-step explanation:

im not that sure

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A certain isotope decays so that the amount A remaining after t years is given by:
pashok25 [27]

f(h(x))= 2x -21

Step-by-step explanation:

f(x)= x^3 - 6

h(x)=\sqrt[3]{2x-15}

WE need to find f(h(x)), use composition of functions

Plug in h(x)

f(h(x))=f(\sqrt[3]{2x-15})

Now we plug in f(x) in f(x)

f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6

cube and cube root will get cancelled

f(h(x))= 2x-15 -6= 2 x-21

3 0
4 years ago
14m+m+17m−9m if m=30
NikAS [45]

Answer:

  690

Step-by-step explanation:

Put 30 where m is in the expression and do the arithmetic. Or, simpify the expression first, then do the same.

  14·30 +30 +17·30 -9·30 = 420 +30 +510 -270 = 690

Simplifying first, you have ...

  14m +m +17m -9m = m(14 +1 +17 -9) = 23m

  23·30 = 690

4 0
4 years ago
Struggling lol. Any help would be appreciated!
Alekssandra [29.7K]

Answer:

Heptagon = 84 ft²

Octagon  = 186 yd²

Triangle = 48√3 m²

Step-by-step explanation:

\textsf{area of a regular polygon}=\dfrac12ap

where:

  • a = length of apothem
  • p = perimeter

<u>Heptagon</u>

a = 5.0 ft

p = 33.6 ft

⇒ area = 1/2 x 5.0 x 33.6 = 84 ft²

<u>Octagon</u>

a = 7.5 yd

p = 8 x 6.2 = 49.6 yd

⇒ area = 1/2 x 7.5 x 49.6 = 186 yd²

<u>Triangle</u>

Formula for the apothem of an equilateral triangle :

a=\dfrac{s}{2\sqrt{3}}  where s = side length

a = 4, so:

4=\dfrac{s}{2\sqrt{3}}

\implies 8\sqrt{3}=s

Now we know the side length, we can calculate the perimeter (p):

p = 3 x 8√3 = 24√3

⇒ area = 1/2 x 4 x 24√3 = 48√3 m²

8 0
2 years ago
If roger wants to run 10 miles by the end of the week. How many more laps will he need to run this week?
Alexxx [7]
How many laps has he ran and what day of the week is it?
6 0
3 years ago
Read 2 more answers
What is the square root of 361
ivann1987 [24]
The answer would be 19. If u have a calculator you can just plug it in though
6 0
3 years ago
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