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RoseWind [281]
2 years ago
14

What set of reflections would carry trapezoid ABCD onto itself?

Mathematics
1 answer:
Ne4ueva [31]2 years ago
6 0
Y=x,x-axis,y=x, y-axis
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Confusion...help please
kifflom [539]

Given:

In triangle KLM, KL = 123 cm and measure of angle K is 35 degrees.

To find:

The length of the side KM to the nearest tenth of a centimeter.

Solution:

In a right angle triangle,

\cos \theta =\dfrac{Base}{Hypotenuse}

In the given right triangle KLM,

\cos K=\dfrac{KM}{KL}

\cos (35^\circ)=\dfrac{KM}{123}

0.819152=\dfrac{KM}{123}

Multiply both sides by 123.

0.819152\times 123=KM

100.755696=KM

KM\approx 100.8

The measure of side KM is 100.8 cm.

Therefore, the correct option is (2).

8 0
2 years ago
Domain: -5 -4 -3.-20. 1. 2. 3. 4. 5)
notsponge [240]
Hdjjddjdjdjdkdidididjskdjdjdidiiddiidididdidididididjdjsksksksksksksksksk
8 0
3 years ago
How is the graph of y=(x-1)2 - 3 transformed to produce the graph of y=
Elodia [21]

Answer:

The graph is stretched vertically by a factor of ½, translated left 5 units, and translated up 3 units.

7 0
2 years ago
An arch is in the shape of a parabola. It has a span of 100 feet and a maximum height of 25 ft.
faltersainse [42]

Answer:

y=-\frac{1}{100}(x-50)^2+25

the height of the arch 10 feet from the center is 24 feet

Step-by-step explanation:

An arch is in the shape of a parabola. It has a span of 100 feet, the vertex lies at the center 50 and the maximum height of 25 ft.

Vertex at (50,25)

vertex form of the equation is

y=a(x-h)^2+k, (h,k) is the center

y=a(x-50)^2+25

the parabola starts at (0,0) that is (x,y)

0=a(0-50)^2+25

subtract 25 from both sides

-25=a(-50)^2

-25=a(2500)

divide both sides by 2500

a=-\frac{1}{100}

y=-\frac{1}{100}(x-50)^2+25

the height of the arch 10 feet from the center.

center is at 50, 10 feet from the center so x=40 and x=60

y=-\frac{1}{100}(40-50)^2+25

y=24

the height of the arch 10 feet from the center is 24 feet

4 0
3 years ago
what is f(x) = 2x2 28x – 5 written in vertex form? f(x) = 2(x 7)2 – 19 f(x) = 2(x 7)2 – 103 f(x) = 2(x 14)2 – 14 f(x) = 2(x 14)2
polet [3.4K]
Hello,
++++++++++++++++++++++
Answer B
++++++++++++++++++++++

2x²+28x-5=2(x²+2*7x+49)-5-2*48
=2(x+7)²-103

++++++++++++++++++++++++++++++
4 0
3 years ago
Read 2 more answers
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