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klio [65]
3 years ago
15

Eric's apartment is 1350 s1quare feet, how many square meters of carpet will he need to order?​

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

He needs to order 125.42\ m^{2} of carpet

Step-by-step explanation:

we know that

1\ ft=0.3048\ m

we have

1,350\ ft^{2}

Convert to m^{2}

1,350\ ft^{2}=1,350(0.3048)^{2}=125.42\ m^{2}

Natasha_Volkova [10]3 years ago
5 0

Answer:

125.42 meter²

Step-by-step explanation:

The area of Eric's apartment = 1350 ft²

1 square feet = 0.3048 square meter

1 square feet (ft²) = 0.09290304 square meter (meter²)

To convert square feet to square meter multiply the square feet value to 0.09290304

1350 ft² = 1350 × 0.09290304 = 125.419104 ≈ 125.42 meter²

He will need 125.42 meter² carpet to order.

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b

Step-by-step explanation:

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3 years ago
Of the Students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of th
soldier1979 [14.2K]

Answer:

\frac{9}{20} students.

Step-by-step explanation:

We have been given that of the students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of the students are also involved in the drama club.

To find the students are both play a sport and a part of the drama club, we need to find 3/5 part of 6/8 as:

\text{Students who play a sport and a part of the drama club}=\frac{6}{8}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3}{4}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3\times 3}{4\times 5}

\text{Students who play a sport and a part of the drama club}=\frac{9}{20}

Therefore, \frac{9}{20} students play sport and part of the drama club.

5 0
3 years ago
Find the surface area of a cube with side length 6 1/2
DaniilM [7]
To find the surface are youd have to multiply 6 1/2 by 6, because a cube has 6 total sides. so the answer would be 6•6.5 which equals 39
5 0
3 years ago
Read 2 more answers
CALCULUS: Determine which function is a solution to the differential equation y ' − y = 0.
Montano1993 [528]

C: none of these are solutions to the given equation.

• If<em> y(x)</em> = <em>e</em>², then <em>y</em> is constant and <em>y'</em> = 0. Then <em>y'</em> - <em>y</em> = -<em>e</em>² ≠ 0.

• If <em>y(x)</em> = <em>x</em>, then <em>y'</em> = 1, but <em>y'</em> - <em>y</em> = 1 - <em>x</em> ≠ 0.

The actual solution is easy to find, since this equation is separable.

<em>y'</em> - <em>y</em> = 0

d<em>y</em>/d<em>x</em> = <em>y</em>

d<em>y</em>/<em>y</em> = d<em>x</em>

∫ d<em>y</em>/<em>y</em> = ∫ d<em>x</em>

ln|<em>y</em>| = <em>x</em> + <em>C</em>

<em>y</em> = exp(<em>x</em> + <em>C </em>)

<em>y</em> = <em>C</em> exp(<em>x</em>) = <em>C</em> <em>eˣ</em>

8 0
2 years ago
Find the value of the expression <br><br> (688 − c) · 222<br><br> for c = 684.
Luba_88 [7]

(688-684) x 222

You have to do what’s in the parentheses first because of PEMDAS

688-684=4

Then you have to multiply

4x222

=888

5 0
3 years ago
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