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3 years ago

Please help me with 1 & 3!

Mathematics

2 answers:

kiruha [24]3 years ago

7 0

On three does it tells you the data

dusya [7]3 years ago

4 0

They both added up all the numbers for each column and then divided by how many numbers there were in total. For example, 1 + 9 + 11 = 21. 21/3 (How many numbers there were added total) would average to 7.

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What is 3/4 written as a percentage

Taya2010 [7]

Answer:

75%

Convert 3/4 to a percent. Begin by converting the fraction 3/4 into decimal. Multiply the decimal by 100 and write the result with the percentage sign: 0.75 × 100 = 75%.

Step-by-step explanation:

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3 years ago

48 is what percent of 120?

Nataliya [291]

Answer:

Step-by-step explanation:

57.6

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2 years ago

Read 2 more answers

What is the relationship among direct variation,lines,rates of change, and slope?

JulsSmile [24]

A direct variation is a proportional equation. Such as:

For every 3 cookies, linda gets 1 glass of milk. The equation for this is y=3x where y is the glasses and x is the cookies. this is a direct variation. It also has a linear line. Linear means straight. Rate of change and slope are the exact same thing. They are the value of 'm' in y=mx+b

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3 years ago

Look at the factors of 18 and 30. What is the greatest common factor? factors of 18: 1, 2, 3, 6, 9, 18 factors of 30: 1, 2, 3, 5

kifflom [539]

Answer:

is number 6

Step-by-step explanation:

the greatest common factor is the largest common factor of those.

3 0

2 years ago

At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul

vampirchik [111]

Answer:

a) Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b) The 95% confidence interval would be given by (910.05;959.95)

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) $z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750$

Since is a bilateral test the p value is given by:

$p_v =2*P(Z>2.750)=0.0059$

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b. What is the 95% confidence interval estimate of the population mean examination score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=935$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=180$ represent the population standard deviation

n=200 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=3278.222$

The sample deviation calculated $s=97.054$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$