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muminat
3 years ago
7

(20 POINTS) PLZZZZZ HELPPPPPP

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

65 ft (which is A)

Step-by-step explanation:

A² + B² = C²

72² + B² = 97²

B² = 4225

B = √4225

B = 65 ft

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What is the value of 1 raised to a negative exponent? Use examples to support your answer.
antoniya [11.8K]

Answer:

1^-1 = 1/1^1 = 1

Step-by-step explanation:

In fact, 1^345 = 1 and 1^-345 = 1

Zero to any power is 0.

1 to any power is 1

5 0
3 years ago
A chef is filling one sink with water, while emptying another. The first sink is empty and is being filled at a rate of 4 gallon
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3 years ago
A flowerbed is to be 3m longer than its width.the flowerbed will have an area of 70m²​
melomori [17]
ANSWER
Yes, it is a quadratic equation which is x² + 3x - 70 = 0

SOLUTION

Area = Length × Width
Let x be the Length, L = x
Length is 3 cm longer than its width, thus, W = x + 3
The Area is equal to 70m², thus, A = 70m²

In Mathematical representation,
A = L × W
70 = (x)(x + 3)
70 = x(x) + x(3)
70 = x² + 3x
0 = x² + 3x - 70
4 0
3 years ago
Ocean tides can be modeled by a sinusoidal function. Suppose that there is a low and high tide every 12 hours, and that high tid
USPshnik [31]

Answer:

(a)y=5sin(\frac{\pi}{6}(x+2))+5

(b) 7.5ft above the low tide.

Step-by-step explanation:

(a) To find the function that computes the height of the tide, you need to select the form of the sinusoidal function. For example, use the form:

y=Asin(B(x-C))+D

Where A is the amplitude, B the frequency, C the phase shift and D the vertical shift.

The  amplitude is half the distance between the highest and the lowest tide:

A=10/2=5ft

The frequency is related to the period T by:

B=\frac{2\pi}{T}

The period is 12 hours, then

B=\frac{2\pi}{12}=\frac{\pi}{6}

The high tide is at 1:00 a.m. and 1:00 p.m. , this is the moment when sin(B(x-C))=1, if sin(\frac{\pi}{2})=1 then B(x-C) must be equal to \frac{\pi}{2} when x=1:

B(x-C)=\frac{\pi}{2}\\\frac{\pi}{6}(1-C)=\frac{\pi}{2}\\\frac{1}{6}(1-C)=\frac{1}{2}\\(1-C)=\frac{6}{2}\\-C=3-1\\C=-2

The vertical shift is the sum of the lowest value, the height of the low tide (lt) and the amplitude:

D=5+lt

The function is:

y=5sin(\frac{\pi}{6} (x+2))+5+lt

Because the function must be the height above low tide height, subtract this heigh from the function:

y=5sin(\frac{\pi}{6} (x+2))+5+lt-lt

y=5sin(\frac{\pi}{6} (x+2))+5

(b) Use x=11 in the function

y=5sin(\frac{\pi}{6} (11+2))+5=2.5+5=7.5ft above the low tide.

3 0
3 years ago
What is the area of this shape
Orlov [11]

Answer:

84m2

Step-by-step explanation:

5 0
4 years ago
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