It’s is 3/78 as the answer to this problem/question you have
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
Answer:
You're correct.
Step-by-step explanation:
Answer:
Step-by-step explanation:
![A_{circle}=\pi r^2\\\\A=\pi r_{walkway}^2-\pi r_{fountain}^2\\\\A=\pi(20^2-16^2)=244\pi](https://tex.z-dn.net/?f=A_%7Bcircle%7D%3D%5Cpi%20r%5E2%5C%5C%5C%5CA%3D%5Cpi%20r_%7Bwalkway%7D%5E2-%5Cpi%20r_%7Bfountain%7D%5E2%5C%5C%5C%5CA%3D%5Cpi%2820%5E2-16%5E2%29%3D244%5Cpi)
use a calculator fo find the value
1/6 yards. All you have to do is add the two upper numbers (numerator) ans then subtract 6/6 - 5/6