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Greeley [361]
3 years ago
10

I need help please help

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
3 0

Answer:

21u-16v+18w

Step-by-step explanation:

(7u-4v+4w) 14u-12v+14w

21u-16v+18w

Alenkasestr [34]3 years ago
3 0

Answer:

= 21u−16v+18w

Step-by-step explanation:

Let's simplify step-by-step.

7u−4v+4w−2(−7u+6v−7w)

Distribute:

=7u+−4v+4w+(−2)(−7u)+(−2)(6v)+(−2)(−7w)

=7u+−4v+4w+14u+−12v+14w

Combine Like Terms:

=7u+−4v+4w+14u+−12v+14w

=(7u+14u)+(−4v+−12v)+(4w+14w)

=21u+−16v+18w

Answer:

=21u−16v+18w

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7 0
3 years ago
Read 2 more answers
Solve x2 + 14x = −24 by completing the square.
Aleks04 [339]

Option A

The solution set of the equation is {-12, -2}

<h3><u>Solution:</u></h3>

Given equation is:

x^2 + 14x = -24

We have to find the solution set of this equation by completing the square

First, rearrange the equation so that only zero will be on the right side:

x^2 + 14x + 24 = 0 ----- eqn 1

<em><u>The general form of quadratic equation is:</u></em>

ax^2 + bx + c = 0 where a \neq 0

On comparing the given eqn 1 with general quadratic equation, we get

a = 1

b = 14

c = 24

In completing the square, we take half of coefficient of middle term "x" and then square it. Then we add it on both sides of the equation

So to complete the square, add (\frac{b}{2})^2 to both sides of the equation

x^2 + 14x + 24 + (\frac{14}{2})^2 = (\frac{14}{2})^2

x^2 + 14x + 24 + 7^2 = 7^2\\\\x^2 + 14x + 24 + 49 = 49

x^2 + 14x + 24 + 49 = 49\\\\x^2 + 14x + 49 = 49 - 24\\\\x^2 + 14x + 49 = 25\\\\(x + 7)(x + 7) = 25\\\\(x + 7)^2 = 25

Take square root on both sides

x + 7 = \sqrt{25}

x+7=\pm 5

Now make two equations

x + 7 = + 5 and x + 7 = -5

x = +5 - 7 = -2

x = -2

And,

x + 7 = -5

x = -5 - 7 = -12

x = -12

Therefore, the solution set of the equation is {-12, -2} and option A is correct

6 0
3 years ago
Read 2 more answers
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