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kondaur [170]
3 years ago
12

There are 84 players on a football team. The ratio of offensive players to defensive players is 4 to 3. How many offensive playe

rs are on the team?
Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0
42 bcz idrc nvm bih idrc abt life
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PLEASE HELP IM STUCK WITH THIS ONE AND I DONT KNOW :(
labwork [276]
The line crossing the two parallel lines forms an allied angle
So using the theory “allied angles add up to 180 degrees” we can find x

76 + x =180
x= 180-76
x=104 (Option B)
6 0
3 years ago
What is the measure of the missing angle?
choli [55]

Answer:

<u><em>85 degrees</em></u>

Step-by-step explanation:

A triangle's angles must add up to 180 degrees.

50 + 45 = 95

180 - 95 = 85

x = 85

4 0
3 years ago
Read 2 more answers
I'm helping someone with her daughter's homework. What is the term for this definition: take a part a number to write it in a ne
mihalych1998 [28]

Answer:

hello mate.. i am glad ur helping someone for her hw.. nice nice

well as per my understanding

'' take apart a number to write it in a new way ''

this answer must be '' subtraction''

as in subtraction we take apart number and resulting number is new way of writing the difference of first 2 ....

go on.. help more ppl ... we are here to support

8 0
3 years ago
Which is the translation of the expression below?
NNADVOKAT [17]
In English, the translation of those symbols is ...

Zero multiplied or divided by anything is zero.
4 0
3 years ago
Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x)
tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF(2^{4}) or GF(24). i believe the question should rather be in this form;

multiplication in GF(2^{4}): Compute A(x)B(x) mod P(x) = x^{4} + x+1, where A(x)=x^{2}+1, and B(x)=x^{3} + x+1.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1  ) = (x^{5} +x^{3}+x^{2}  ) + (x^{3}+x+1  ) mod (x^{4} + x+1 )

= x^{5}+2x^{3} +x^{2}  + x + 1 mod(x^{4}+x+1  )

=2x^{2} +1

please note that the division by the modulus above we used

\frac{x^{5}+2x^{3}+x^{2} +1  }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}

5 0
3 years ago
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