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SSSSS [86.1K]
3 years ago
8

I am a 2-digit number. The sum of my digits is 11. I am divisible by both 4 and 7

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0

Answer:

56 or 84

Step-by-step explanation:

Setler [38]3 years ago
6 0

Answer:

It's 56

Step-by-step explanation:

  • We have 2 digit number
  • the sum of digits is 11  and it is divisible by 4 and 7
  • so, first possibility is 4×7=28 ; but the sum of digits is 11; so,the sum of                digits is 2+8=10 which does not satisfies the first constraint
  • next possible 2 digit number is 56: since the sum of digits is 5+6=11, 56 ÷ 7 = 8 , 56 ÷ 4 = 9
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Rudik [331]

Answer:

y = -5x/3 + 18

Step-by-step explanation:

The points can be written as;

(x,f(x))

where f(x) is same as y

So the points we have are;

(6,8) and (9,3)

We start by finding the slope or the line connecting the points

m = y2-y1/x2-x1 = (3-8)/(9-6) = -5/3

So now we have the general form of a linear equation as

y = mx + b

where m is slope and b is y intercept

We already have slope and we want to calculate y-intercept

Simply substitute one of the points

(9,3) in this case

9 for x and 3 for y

we have ;

y = -5x/3 + c

3 = -15 + c

c = 18

So the line equation is;

y = -5x/3 + 18

3 0
3 years ago
I NEED HELP ASAP PLEASE 07.02 MC) An equation is shown below: 3(2x – 7) = 3 Part A: How many solutions does this equation have?
horsena [70]

Answer:

<h3>              A:  One</h3><h3>              B:  x = 4     </h3>

Step-by-step explanation:

3(2x - 7) = 3

÷3           ÷3

2x - 7  =  1

+7        +7

 2x  =  8

÷2      ÷2

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6 0
3 years ago
Read 2 more answers
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vekshin1

Answer:

{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}

Step-by-step explanation:

sinx can run from -1 to +1

2sinx can run from -2 to +2

2sinx -1 can run from -3 to +1

However, the square root is imaginary when x < 0. So, the condition is

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2sinx ≥ 1

sinx ≥ ½

x ≥ π/6 (30°)

So, in the interval [0, 2π], π/6 ≤ x ≤ 5π/6

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Over all real numbers, the condition is (π/6 +2πn) ≤ x ≤ (5π/6 + 2πn).

The domain is then

{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}

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3 years ago
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Step-by-step explanation:

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allsm [11]
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