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2 years ago

90 POINTS!! Right answers will earn brainly.

Mathematics

1 answer:

sveticcg [70]2 years ago

3 0

Answer:

I believe the Science Students have a higher average grade on their respective tests.

Step-by-step explanation:

The mathematics students all scored between 30-40 on their test while the science students scored between 40-50%. This shows that the science students had a larger average score. Hope this helps! Have a great day :)

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Square root3(square root3+2square root12) simplify it.Answer should be square root 3.

julsineya [31]

Answer:

sqrt3[sqrt3+2sqrt12]=sqrt3[sqrt3+4sqrt3] = sqrt3[5sqrt3= 3x5 =15

5 0

2 years ago

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Which is the most efficient method?

marysya [2.9K]

Hello!

The answer to your question is A. Elimination.

Have a good day! -Wajiha

8 0

3 years ago

[(-6) + 5] ÷ [(-2) + 1]

Ira Lisetskai [31]

Answer:

Answer is 1

Explanation:

(-6 + 5) / (-2 + 1)

-1 / -1

1

3 0

3 years ago

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Determine the rational zeros for the function f(x)=x^3+7x^2+7x-15

alexandr402 [8]

Answer:

1,-3,-5

Step-by-step explanation:

Given:

f(x)=x^3+7x^2+7x-15

Finding all the possible rational zeros of f(x)

p= ±1,±3,±5,±15 (factors of coefficient of last term)

q=±1(factors of coefficient of leading term)

p/q=±1,±3,±5,±15

Now finding the rational zeros using rational root theorem

f(p/q)

f(1)=1+7+7-15

f(-1)= -1 +7-7-15

= -16

f(3)=27+7(9)+21-15

=96

f(-3)= (-3)^3+7(-3)^2+7(-3)-15

= 0

f(5)=5^3+7(5)^2+7(5)-15

=320

f(-5)=(-5)^3+7(-5)^2+7(-5)-15

f(15)=(15)^3+7(15)^2+7(15)-15

=5040

f(-15)=(-15)^3+7(-15)^2+7(-15)-15

=-1920

Hence the rational roots are 1,-3,-5 !

4 0

3 years ago

Read 2 more answers

Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob

miskamm [114]

Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

$P(x)=^nC_x p^x q^{n-x}$

Where, $^nC_x=\frac{n!}{x!(n-x)!}$

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

$^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}$

$=36(0.12)^2 (0.88)^7+84(0.12)^3 (0.88)^6$

$=0.279266611163$

$\approx 0.28$

$=28\%$

7 0

3 years ago