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KatRina [158]
3 years ago
7

Compare using <, >, = 5+(-4)____-4 + (-7)

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Good morning,

Answer:

<h2>5+(-4) > -4 + (-7)</h2>

Step-by-step explanation:

5+(-4) = 5 - 4 = 1

-4 + (-7) = -(4+7) = -11

since  1 > -11 then 5+(-4) > -4 + (-7)

:)

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How to find matrics M
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\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]

(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1

(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]

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3 years ago
Please help me in this one!!
olga2289 [7]
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Find how many years it would take for an investment of $3700 to grow to $6000 at an annual interest rate of 6.2% compounded semi
lorasvet [3.4K]

Answer:

  7 years 11 months

Step-by-step explanation:

The future value formula for the value of a principal P invested at annual rate r compounded n times yearly for t years is ...

  FV = P(1 +r/n)^(nt)

For the given numbers, we want to find t:

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Dividing by 3700 and taking the logarithm, we get ...

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  log(60/37) = 2t·log(1.031)

Dividing by the coefficient of t gives ...

  t = log(60/37)/(2log(1.031)) ≈ 7.92 . . . . . years

It will take about 7 years 11 months for the investment to grow to $6000.

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Answer:

16x+9

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