Ask question

Ask question

All categories

4 years ago

12

The scale on a map is 1 in. : 50 mi. The actual distance between the two cities is 350 miles. What is the distance between the c

ities on the map?

1 answer:

Luba_88 [7]4 years ago

6 0

The answer is 7 because when you divide 50 from 350 I️t gives you seven.

Hope this helped!!!!!!!!!!!!

You might be interested in

Mike scored a 125 at a semi-final dividing competition season. He scored 95 at this final season. What is the percentage decreas

IrinaK [193]

Answer:

There was a 24% decrease

Step-by-step explanation:

Percentage decrease = (final season's score - semi-final score) / semi final score x 100

$\frac{95-125}{125}$ ×100

$\frac{-30}{125}$ × 100 = -24%

3 0

3 years ago

What is 10 - (-18) in a integer

torisob [31]

Answer:

28

Step-by-step explanation:

10 - (-18)

=> 10 + 18

=> 28

Hoped this helped.

3 0

3 years ago

Read 2 more answers

THOROUGHLY EXPLAIN how this is done plz

prisoha [69]

First and last terms of the given equation are perfect squares. They can be written as

(4p^2)^2+ 2.(4p^2).5+(5)^2
It's like identity 1: (a+b)^2=a^2+2ab+b^2
So a=4p^2 and b=5
Therefore it is equal to (4p^2+5)^2

8 0

4 years ago

PLZ HELP ASAP !!! MARKIN BRAINIEST !!!

vovikov84 [41]

Answer:

PLZZZZ I WANT BRAINIEST IM ONLY IN MIDDLE SCHOOL PLZZZZ BRAINIEST!

Step-by-step explanation:

4 0

4 years ago

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

4 years ago