. , FG = 40, RS = 40, OP = 15. Find x. 20 15 21 17
1 answer:
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Answer:
Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Step-by-step explanation:
We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.
Let X = <u><em>amount a Niffler can hold in their pouch</em></u>
So, X ~ Normal()
The z score probability distribution for normal distribution is given by;
Z = ~ N(0,1)
where, = population mean = 25 pounds
= standard deviation = 6.8 pounds
Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)
P(X > 32 pounds) = P( >
) = P(Z > 1.03) = 1 - P(Z
1.03)
= 1 - 0.8485 = 0.1515
<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>
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Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.
Answer:
C. increases rapidly.
Step-by-step explanation:
tan(θ) = sin(θ)/cos(θ)
Now, when sin 90 = 1
and cos 90 = 0
so, tan(90) = 1/0 = not defined.
<em>(1/0 is infinity and its value is not defined)</em>
So, when angle θ increases to 90°, then the value of tan(θ) increases rapidly, as shown in the figure below.
