Well, you can start by putting the slopes and lengths on the right side (Where is says slope of A'B'). The slopes will be the same, so Slope of AB is still 5 and Slope of BC is still 0.25. When you get to the lengths, just multiply it by 1.2. The length for Length of CD is 5.4 and Length of AD is 8.4
Here's what it should look like:
Slope of A'B' ⇔ 5
Slope of B'C' ⇔ 0.25
Length of C'D' ⇔ 5.4
Length of A'D' ⇔ 8.4
Answer:41 m
Step-by-step explanation:
Lets use the Pythagoras thermos to solve
40^2+9^2=c^2
1600+81=c^2
1681=c^2
41=c
The value of the hypotenuse is 41
I see you already attempted this question and got it right, Good job!
Answer:
Part A: Options D and E
Part B: Disagree
Step-by-step explanation:
Part A:
From the graph attached,
Option A
The object is launched from the ground.
False.
Since, the object is launched from the 5 feet above the ground.
Option B
The flight is symmetric about the line t = 10
False.
Since, the flight is symmetric about the line t = 12
Option C
The object reaches a maximum height of 12 feet.
False.
At t = 12 seconds maximum height of the object = 19.4 feet
Option D
The object is flying in the air during the interval 0 < t < 25.93
True.
Option E
The object reaches its maximum height after 12 seconds of flight.
True.
After 12 seconds object is at the maximum height 19.4 feet.
Therefore, Options D and E are the correct options.
Part B:
From the table attached,
h(4) = 13
h(20) = 13
At t = 4 and 13 seconds height of the object is same.
h(4) = h(20)
But Timothy said h(4) < h(20)
Therefore, disagree with the statement of Timothy.
im totally confused by this question