Question

What is an equation of the line that passes through the point (-5,-2)(−5,−2) and is parallel to the line x-y=5x−y=5?

Answer 1

Answer:

x-y+3 = 0

Step-by-step explanation:

Given,

Point = (-5,-2).

Equation of parallel line = x-y = 5

Slope of the required will be same as that of the parallel line.

So, Slope of parallel line

x - y = 5

y = x - 5

Slope of parallel line is 1.

equation of line passing through point (-5,-2) with slope 1.

$(y-y_1)= m(x-x_1)$

(y+2) = 1 (x+5)

x-y+3 = 0

Hence, equation of line is equal to x-y+3 = 0.