14 and 11
let x be the second number then the first number = x + 3 ( 3 more than second)
Also 3(x + 3) = 5x - 13
3x + 9 = 5x - 13
subtract 3x from both sides
9 = 5x - 3x - 13
9 = 2x - 13
add 13 to both sides
22 = 2x
divide both sides by 2
11 = x → second number
first number = x + 3 = 11 + 3 = 14
Answer:
B
Step-by-step explanation:
quadratic formula:
x = [-b ± sqrt(b^2 - 4ac)] / 2a
1. find a, b, and c
a = 1
b = -3
c = 1
2. plug values into formula
x = [3 ± sqrt(9-4•1•1)] / 2
3. simplify
x = [3 ± sqrt(5)] / 2
This is B.
The answer is 11/12 , when getting the answer you have to get common denominator so you’d do 1/4 X 3 and you’ll get 3/12 then after all you do is add the numerator , hope this helped !
(a) algebraically
(f ° g)(x) = f(g(x))
(f ° g)(x) = f(3 - x/4)
(f ° g)(x) = 3 - 4(3 - x/4)
(f ° g)(x) = x
(g ° f)(x) = g(f(x))
(g ° f)(x) = g(3 - 4x)
(g ° f)(x) = (3 - (3 - 4x))/4
(g ° f)(x) = x
since both ways ended up with “x” as their answers that means they are inverse of each other. i found this doing it algebraically.
i hope this was helpful!