Answer:
A. 9
Step-by-step explanation:
A counterexample shows that one side is true while the other is false
x>7 and x>11
sub in the answers
9>7 and 9>11 -this is true for the first half but false for the second
5>7 and 5>11 -this is false for both
13>7 and 13>11 -this is true for both
15>7 and 15>11 -this is true for both
Answer A is correct as it proves the statement to be incorrect
Determine the defined range k=0
move expression to the left side and change its sign so it would be the problem = 0
write all numerators above the least common denominator 6k (*2*)-Squared
calculate the sum or the difference
check the solution in the defined range
hope this helped you
It would be letter D - 3648.
The probability of winning is 0.76 and the probability of losing is 0.24.
In each simulation the probability of winning exactly one match is: P(win one match) = 2C1 x 0.76 x 0.24 = 0.3648
Multiply the result by 10,000 simulations to get the expected number of times that exactly one match is won.
10,000 x 0.3648 = 3648 times.
Answer:
u=91
Step-by-step explanation:
-2=u-93÷-3
multiply both sides by 3
3(-2)=(u)3+(-93÷-3)3
-6=3u-279
add 279 to both sides
-6=3u-279
+279. +279
273=3u
divide by 3
273÷3=3u÷3
91=u
Answer:
The answer is the last option, D.
Step-by-step explanation:
A function with one solution can be added and have a variable and a constant leftover. The variables in the other three options cancel each other out, so none of them have one solution. The first and third equations have no solutions, and the second has infinitely many solutions. The fourth option has only one variable cancel out and still has a constant on the other side of the equation. The fourth option is correct.
