If a hat costs 15$ and the sales tax is 10% how much money do you need to buy the hat

−6>−30−4x<br> help please

nikklg [1K]

from both sides of the equation.

Answer:

Apply the distributive property.

6 ⋅ 5 + 6 (-3x) = -4 x - 12

Multiply

6 by 5 . 30 + 6 (-3 x) = - 4 x - 12

Multiply

− 3 by 6 . 30 - 18 x = - 4 x - 12

Add

4 x to both sides of the equation.

30 - 18 x + 4 x = - 12

Add

− 18 x and 4 x . 30 - 14 x = - 12

Subtract

30

from both sides of the equation.

- 14 x = - 12 - 30

Subtract

30 from

− 12 . - 14 x = - 42

x = 3

Step-by-step explanation:

6 0

3 years ago

Write the standard form of the equation of the circle with the given characteristics. Center: (3, 5); Solution point: (−2, 17)

Angelina_Jolie [31]

$\text{we know that the general equation of the circle is }\\
\\
(x-h)^2+(y-k)^2=r^2\\
\\
\text{where, (h,k) is the center of the circle and r is the radius.}\\
\\
\text{Given that the centered of the circle is at }(h,k)=(3,5)\\
\text{and a solution point on circle is (-2,17).}\\
\\
\text{so the radius of the circle will be the distance between center and the }$

$\text{solution point. so using the distance formula, we have}\\
\\
\text{Radius, }r=\sqrt{(-2-3)^2+(17-5)^2}\\
\\
\Rightarrow r=\sqrt{25+144}\\
\\
\Rightarrow r=\sqrt{169}\\
\\
\Rightarrow r=13\\
\\
\text{Hence using the standard for of circle, equation of circle with center}\\
(h,k)=(3,5) \text{ and radius r=13 is}\\
\\
(x-3)^2+(y-5)^2=(13)^2\\
\\
\Rightarrow (x-3)^2+(y-5)^2=169$

3 0

3 years ago

Show your mastery of equivalent and simplifying fractions by using the sketchpad below to write the fraction

Sphinxa [80]

Answer: 2/3 (two thirds)

Explanation: Divide both denominator and numerator by the common factor of fourteen

3 0

3 years ago

Can you show how you did it?<br> 8.31 - 3.43 =

d1i1m1o1n [39]

Answer:

4.68

Step-by-step explanation:

Remember to line up the decimal point. Subtract as ordinarily.

8.31

-3.43

--------

4.68

4.68 is your answer

~

7 0

3 years ago

What kind of problem do we need to use “indefinite integral” to solve? Use a real life example to explain.

anastassius [24]

Answer:

Indefinite integration acts as a tool to solve many physical problems.

There are many type of problems that require an indefinite integral to solve.

Basically indefinite integration is required when we deal with quantities that vary spatially or temporally.

As an example consider the following example:

Suppose that we need to calculate the total force on a object placed in a non- uniform field.

As an example let us consider a rod of length L that posses an charge 'q' per meter length and suppose that we place it in a non uniform electric field which is given by

$E(x)=\frac{E_{o}}{e^{kx}}$

Now in order to find the total force on the rod we cannot use the similar procedure as we can see that the force on the rod varies with the position of the rod.

But if w consider an element 'dx' of the rod at a distance 'x' from the origin the force on this element will be given by

$dF=E(x)\times qdx\\\\dF=\frac{qE_{o}}{e^{kx}}dx$

Now to find the whole force on the rod we need to sum this quantity over the whole length of the rod requiring integration, as shown

$\int dF=\int \frac{qE_{o}}{e^{kx}}dx$

Similarly there are numerous problems considering motion of particles that require applications of indefinite integration.

4 0

3 years ago