Question

unit vector lies in the xy plane, at an angle of 145 degrees from the +x axis, with a positive y component. What is the unit vector?

Answer 1

Answer:

$-0.82i+0.57j$

Step-by-step explanation:

We are given that a unit vector A which lies in the xy-plane.

Unit vector:It is that vector whose magnitude is equal to 1.

$\mid A\mid=1$

$\theta=145^{\circ}$

We have to find the unit vector.

x-component of unit vector=$A_x=\mid A\mid cos\theta$

x-component of unit vector=$A_x=1cos145^{\circ}=-0.82$

y-component of unit vector=$A_y=\mid A\mid sin\theta=1\times sin145=0.57$

Unit vector ,A=$A_xi+A_yj=-0.82i+0.57j$

Hence, the unit vector =$A=-0.82i+0.57j$