For a monic quadratic (factor of 1 on
) we always add half the coefficient on the linear (
) term, so
![\left(\dfrac 7 2\right)^2 = \dfrac{49}{4}](https://tex.z-dn.net/?f=%20%5Cleft%28%5Cdfrac%207%202%5Cright%29%5E2%20%3D%20%5Cdfrac%7B49%7D%7B4%7D)
Answer: 49/4
![x^2 + 7x + \dfrac{49}{4} = 4 + \dfrac{49}{4}](https://tex.z-dn.net/?f=x%5E2%20%2B%207x%20%2B%20%5Cdfrac%7B49%7D%7B4%7D%20%3D%204%20%2B%20%5Cdfrac%7B49%7D%7B4%7D)
![(x + \frac 7 2)^2 = 4 + \frac{49}{4}](https://tex.z-dn.net/?f=%28x%20%2B%20%5Cfrac%207%202%29%5E2%20%3D%204%20%2B%20%5Cfrac%7B49%7D%7B4%7D)
<span>The answer is 1 times 29. Number 29 is a prime number, which means that its multiples are 1 and itself (29). 29 = 29 * 1. According to the commutative law, in addition and multiplication, numbers can be swapped but the result will remain the same: a+b=b+a or a*b=b*a. Therefore, 29 = 29 * 1 = 1 * 29. In other words, 29 times 1 equals 29 and 1 times 29 equals 29, too.</span>
Hi there! The answer is 10 miles.
Let the distance be represented by b.
The cost if the ride will therefore be
$5 + ( $3.70 × d )
We end up with the following equation
![5 + 3.7d = 42](https://tex.z-dn.net/?f=5%20%2B%203.7d%20%3D%2042)
Subtract 5 from both sides.
![3.7d = 37](https://tex.z-dn.net/?f=3.7d%20%3D%2037)
Divide both sides by 10.
![d = \frac{37}{3.7} = 10](https://tex.z-dn.net/?f=d%20%3D%20%20%5Cfrac%7B37%7D%7B3.7%7D%20%20%3D%2010)
Therefore, Emma had a taxi ride of 10 miles.
178-35=143
143/5= 28.6
he paid $28.6 every month
Slope is rise over run or
(y1-y2)/(x1-x2)
(x,y)
x1=17
x2=-11
y1=-6
y2=7
slope=(-6-7)/(17-(-11))=(-13)/(17+11)=(-13)/(28)=
the slope is -13/28