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ad-work [718]
3 years ago
11

Please help!!! i don’t understand this

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

B. is your answer.

Step-by-step explanation:

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Find the slope of
Anon25 [30]

Answer:

(8,-9)

Step-by-step explanation:

using the principle of vectors, you match each number to their coordinates and add them

so we have (7+1,-12+3)

which is equal to (8,-9)

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2 years ago
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The variable z is inversely proportional to x. When x is 16, z has the value 0.875. What is the value of z when x= 21?
ziro4ka [17]
For z and x to be inversely proportional, there must be some constant k such that

zx=k

Given that z=0.875 when x=16, it follows that

0.875\cdot16=k\implies k=14

Then when x=21, we have

21z=14\implies z=\dfrac{14}{21}=\approx0.667
8 0
3 years ago
Find the total number of unit cube that fill the entire prism
Nonamiya [84]

Answer:

72 cubes

Step-by-step explanation:

Attached is the picture drawn (though not great one), showing 6 cube on length of prism, 3 cubes on width and 4 cubes on height of prism.

Given: Length of prism= 6

           Width= 3

            Height= 4

To know the number of cubes, which can fill the entire prism, we need to find volume of prism.

∴ Volume of prism= length\times width\times height

Volume of prism= 6\times 3\times 4= 72

∴ 72 units of cube can fill the entire prism.

3 0
2 years ago
In 1789, the dimensions expanded to 96 feet by 32. What was the perimeter?
irakobra [83]
The perimeter is 256 feet.

96 + 96 + 32 + 32 = 256.
8 0
3 years ago
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Lori creates the following design for a T-shirt.
kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


6 0
3 years ago
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