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kicyunya [14]
3 years ago
9

Given p(x) = 2x3 − 8x2 + 13x − 21, ___ is a factor because ___.

Mathematics
1 answer:
lyudmila [28]3 years ago
8 0
<span>Given p(x) = 2x3 − 8x2 + 13x − 21, x - 3 is a factor because p(3) = 0. </span>
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Factor wheels show all the
Zielflug [23.3K]

answer: 2 × 2 × 2 × 2 × 2 = 32

Step-by-step explanation:

32 \\  = 16 \times 2  \\ = 4 \times 4 \times 2  \\ = 2 \times 2 \times 2 \times 2 \times 2

3 0
2 years ago
What is the volume of the following triangular prism?
BlackZzzverrR [31]

Answer: 3000cm3

To find the area you need to find the area of the triangle and multiply that by the height of the prism.

The area of the triangle is

.5*12*10 = 60

And the height is .5m = 50cm

So the area will be

60*50 = 3000

7 0
4 years ago
Read 2 more answers
Laura answered 27 questions correct on a test on her test and scored 90%. How many questions where on the test?
Nadya [2.5K]

The number of questions in the test is 30

Step-by-step explanation:

Let's call the total number of questions in the test N.

We know that Laura answered 27 questions, and these 27 questions represent the 90% of the test.

Therefore, we can say that 27 is the 90% of N.

Re-writing the percentage as a fraction,

90\% = 0.90

This means that:

0.90 N = 27

And now we can solve for N to find the number of questions in the test:

N=\frac{27}{0.90}=30

Learn more about percentage:

brainly.com/question/82877

brainly.com/question/1834017

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8 0
3 years ago
Find inverse of y=1/2x+3
yKpoI14uk [10]

Answer:  f⁻¹(x)=2x-6

Step-by-step explanation:

To find the inverse of an equation, you replace y with x and x with y. Then, you solve for y.

y=1/2x+3          [replace y with x and x with y]

x=1/2y+3          [subtract both sides by 3]

x-3=1/2y           [multiply both sides by 2]

y=2(x-3)            [distribute]

y=2x-6

Now, we know the inverse function is f⁻¹(x)=2x-6.

8 0
3 years ago
Solve for a. r=ab/a+b+c
Marta_Voda [28]

Answer:

r(A + B) = rA + rB,. (4). (r + s)A = rA + sA,. (5) r(sA)=(rs)A;. (6). A(BC)=(AB)C,.

4 0
3 years ago
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