1) Let's first find how many calories a runner burns on 1 km: R=120/1.6= 75 (calories/km)
2) On 5 km he will burn: Calories=5*R=5*75= 375 (calories)
______
375 calories he would burn on 5 km.
12 and 1/4 Inches is the distance between the cafeteria and the science lab
LCM of 9 and 30 is 90
Its 90 a^2b^2c^3
Answer:
1
Step-by-step explanation:
only one straight line can be passed through two points
