All categories

2 years ago

Which interval notation represents the set of all numbers from o to 11, inclusive?

Mathematics

1 answer:

Tasya [4]2 years ago

7 0

Answer:

[0,11]

Step-by-step explanation:

Required

Represent Set of numbers from 0 to 11

<em>In interval notation; the square bracket [ ... ] implies that the number in question is inclusive of the set.</em>

So; Given that

Beginning = 0

End = 11

The interval notation can be represented as [0,11] because both numbers are inclusive of the set.

You might be interested in

a runner wants to run 1000 miles in one year. if he runs the same number everyday, use compatible numbers to estimate the number

vampirchik [111]

2.73972603 or ... you can round to the nearest tenth... 2.7

7 0

3 years ago

Read 2 more answers

Given f(x) = 9x - 10, find f(8) *

Rama09 [41]

Answer:

$\huge\boxed{f(8) = 62}$

Step-by-step explanation:

$\sf f(x) = 9x-10\\\\Put\ x = 8\\\\f(8) = 9(8) -10\\\\f(8) = 72-10\\\\f(8) = 62\\\\\rule[225]{225}{2}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

3 0

3 years ago

Read 2 more answers

85 x 63 whoever gets it gets braiest

Katena32 [7]

<span>85 x 63 = 5355

hope it helps

---------------------</span>

6 0

3 years ago

Read 2 more answers

BC=CD what is the property

Andre45 [30]

Distributive Property AB + AB = 2AB

Reflexive Property m>B = m>B

Symmetric Property If AB + BC = AC then AC = AB + BC

Transitive Property If AB ≅ BC and BC ≅ CD then AB ≅ CD

5 0

2 years ago

Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years old. How large a sample size

julsineya [31]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641$

And rounded up we have that n=16641

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

For this case we can use as estimator for the proportion $\hat p =0.5$ , since we don't have any other previous info. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641$

And rounded up we have that n=16641

8 0

2 years ago