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Shtirlitz [24]
3 years ago
5

Buddy guy!!, has anyone noticed that mos thanks have bats literally lots of there names r like dome7

Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

yes i noticed that

Step-by-step explanation:

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2/2 <= x < 8/2
1 <= x < 4
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Write the equation of a linear function f, such that f(1)=4 and f(4)=1 Then find f(-2)
trapecia [35]

If <em>f(x)</em> is a linear function, then

<em>f(x)</em> = <em>ax</em> + <em>b</em>

for some constants <em>a</em> and <em>b</em>.

Given that <em>f</em> (1) = 4 and <em>f</em> (4) = 1, these constants are such that

<em>f</em> (1) = <em>a</em> + <em>b</em> = 4

<em>f</em> (4) = 4<em>a</em> + <em>b</em> = 1

Solve for <em>a</em> and <em>b</em> : eliminate <em>b</em> by subtracting the two equations,

(<em>a</em> + <em>b</em>) - (4<em>a</em> + <em>b</em>) = 4 - 1

-3<em>a</em> = 3

<em>a</em> = -1

Then

-1 + <em>b</em> = 4

<em>b</em> = 5

So we have

<em>f(x)</em> = -<em>x</em> + 5

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3 years ago
the table and a graph both represents the same relationship. Which equation also represents that relationship?
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After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only four women among the last
Afina-wow [57]

Answer:

P(at most four) = 0.00960541

Step-by-step explanation:

For each employee hired, there are only two possible outcomes. Either it is a women, or it is not. The probability of an employee being a women is independent of any other employee, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

19 new employees.

This means that n = 19

Approximately equal number of qualified men as qualified women.

This means that p = 0.5

Probability of getting four or fewer women when 19 people are hired

This is:

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{19,0}.(0.5)^{0}.(0.5)^{19} = 0.00000191

P(X = 1) = C_{19,1}.(0.5)^{1}.(0.5)^{18} = 0.00003624

P(X = 2) = C_{19,2}.(0.5)^{2}.(0.5)^{17} = 0.00032616

P(X = 3) = C_{19,3}.(0.5)^{3}.(0.5)^{16} = 0.00184822

P(X = 4) = C_{19,4}.(0.5)^{4}.(0.5)^{15} = 0.00739288

Then

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.00000191 + 0.00003624 + 0.00032616 + 0.00184822 + 0.00739288 = 0.00960541

So

P(at most four) = 0.00960541

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The larger number is 51 and the smaller number is 12 . ( hope this helped have a good day )
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