If it has no real solutions, that means the graph does not intersect the x axis
since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up
so 'a' must be positive
if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
Answer:
50
Step-by-step explanation:
would it be 50 because you the q to the power of 2 is 2q. Then you would subtract to the other side of the equation so it would be -100=-2q. After you would divided the -2 in -2q on both sides and -100/-2 is 50. So your answer is q=50
Answer:
-60x + 10
Step-by-step explanation:
-5 x 2(6x - 1)
-10 (6x - 1)
-60x + 10
Amount = P(1 + r/t)^nt = 2033.88(1 + 0.039/2)^(11 x 2) = 2033.88(1 + 0.0195)^22 = 2033.88(1.0195)^22 = 2033.88(1.5294) = $3110.60
