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IrinaVladis [17]
3 years ago
8

There are 3 white marbles and 7 blue marbles in a bag.Jamie will randomly pick two marbles out of the bag without replacing the

first marble chosen. What is the probability of jamie' s picking 2 white marbles?
A. 1/15
B.1/18
C.1/20
D.1/7
PLEASE HELP
Mathematics
2 answers:
finlep [7]3 years ago
8 0
(3/10)*(2/9)=6/90 which reduces to 1/15 which is A
masha68 [24]3 years ago
8 0

Answer: A. \frac{1}{15}

Step-by-step explanation:

Given: The number of white marbles = 3

Total number of marbles =3+7=10

Since, Jamie will randomly pick two marbles out of the bag without replacing the first marble chosen.

The probability of Jamie' s picking 2 white marbles is given by :-

\text{P(2 white)}=\frac{3}{10}\times\frac{2}{9}=\frac{1}{15}

Hence, the probability of Jamie' s picking 2 white marbles =\frac{1}{15}

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Cerrena [4.2K]

Answer:

{ \boxed{ \bf{c}}} \:   \: \frac{3.8}{4}  = s

Step-by-step explanation:

{ \tt{4 \: pies \:  =   \: 3.8 \: ounces}} \\ { \tt{1 \: pie \:  =  \: ( \frac{1}{4}  \times 3.8) \: ounces}} \\ { \tt{ = 0.95 \: ounces}}

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5 0
2 years ago
A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged by
Nuetrik [128]

<u>solution</u>

W=f×d×cos theta

=25N×16m×cos 45°

=400Nm×cos 45°

=282.84J

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7 0
3 years ago
Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
2 years ago
7/8 - 6/7. what is the answer.???
lesantik [10]

Answer:

0.0178 is the answer

6 0
1 year ago
Please answer this quickly
tester [92]

Answer:

C. 5x + 11 = 36

Step-by-step explanation:

You can see in the diagram that there are 5 x variables and eleven which make up the total diagram that says 36 so it would have to be 5x+11 = 36

4 0
2 years ago
Read 2 more answers
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