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4 years ago

HELPPP PLEASE DUE NOW

Mathematics

1 answer:

lidiya [134]4 years ago

4 0

The angles that are 105º and (13x + 66)º are the same amount.
105 = 13x + 66
Subtract 66 from each side
39 = 13x
Divide each side by 13
3 = x

Now for z.
Since two equal angles equal 105º each, multiply it by 2 to get 210.
The whole thing is 360º.
360 - 210 = 50
Divide it by 2 to get one of the angles
50 / 2 = 25
z = 25º

Hope this helps!

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3 years ago

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The table represents the observed number of leaves y on x branches of a tree. Calculate the rate of change between 3 and 4 branc

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

The rate of change of number of tree y on x branches of a tree is expressed as shown;

m = Δy/Δx where;

m is the rate of change

Δy is the change in number of leaves between 3 and 4

Δx is change in number of branches between 3 and 4

m = Δy/Δx = y₂-y₁/x₂-x₁

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3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$