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Montano1993 [528]
3 years ago
15

What is 0.03÷558 ? With the steps

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0
0.03 = 3/100
558 = 558/1

3/100 ÷ 558/1 = 3/100 X 1/558 = 1/100 X 1/186 (÷3)

1/100 X 1/186 = 1/18600 (0.0000537634/5.537634 X 10 to the power of 5)
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When the chef turned the new freezer on, the temperature on the internal thermometer was 2 °C.
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Answer: -13 °C.

Step-by-step explanation:

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2 years ago
Help me find Sample variance and standard deviation
AnnZ [28]
First, find the mean. You'll need it to compute the variance.

\bar x=\displaystyle\frac15\sum_{i=1}^5x_i=\dfrac{21+10+6+7+11}5=11

The variance of the sample is then computed with the formula

s^2=\displaystyle\dfrac1{5-1}\sum_{i=1}^5(\bar x-x_i)^2=\dfrac{(21-11)^2+\cdots+(11-11)^2}4=\dfrac{71}2=35.5

The standard deviation is the square root of the variance, so

s=\sqrt{35.5}\approx5.958
5 0
3 years ago
If you are traveling 543 miles and you know that your car gets 18 miles per gallon of gasoline, approximately how many gallons o
Inga [223]

we know that

the car gets 18 miles per -----------> 1 gallon of gasoline

so

for 543 miles ---------------------> x gallons of gasoline


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543/18=x/1---------->x=543/18------->x=30.17 gallons


therefore


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30.17 gallons

6 0
3 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

8 0
3 years ago
Read 2 more answers
Please help me on this question! ​
Fofino [41]

Answer:

L = √(5² + 10² + 7²) = √174 in

Step-by-step explanation:

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3 years ago
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