Write the equation of the line PERPENDICULAR to y = 3/2x + 6 that passes through the point (-3, 4).
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Answer:
The equation in standard form is:
Rx+Py = -PR
Step-by-step explanation:
The slope-intercept form of the line equation
where
- m is the slope
- b is the y-intercept
Given
The y-intercept (0, -R)
The x-intercept (−P, 0)
Finding the slope between (0, -R) and (−P, 0)
Thus, the slope between (0, -R) and (−P, 0) is:
We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.
We are given the y-intercept point (0, −R).
Thus, y-intercept b = -R
so substituting b = -R and in the slope-intercept form to determine the line of the equation
So, the slope-intercept form of the line equation is:
Converting the slope-intercept form of the line equation into standard form
As we know that the equation in the standard form is
Ax+By=C
where x and y are variables and A, B and C are constants
As
so converting into standard form
Multiply the equation by P
Py = -Rx - PR
Add -Rx to both sides
Rx+Py = -Rx - PR + -Rx
Rx+Py = -PR
Therefore, the equation in standard form is:
Rx+Py = -PR