Question

Where does the graph of y= sin x from x = 0 to x = 2n1 start?

Answer 1

Answer:

Step-by-step explanation:

when x=0,sin x=0

when x=30° or π/6

sinx=1/2=0.5

when x=45° or π/4

sin x=√2/2≈1.414/2≈0.707

when x=60° or π/3

sinx=√3/2≈1.732/2≈0.866

when x=90° or π/2

sin x=1

when x=120° 2π/3

sin 120=sin (180-60)=sin 60 ≈0.866

when x=135° or 3π/4

sin 135=sin (180-45)=sin 45≈0.707

when x=150° or 5π/6

sin 150=sin (180-30)=sin 30=0.5

when x=180 or π

sin 180=sin(180-0)=sin 0=0

when x=210° or 7π/6

sin 210=sin (180+30)=-sin 30=-0.5

when x=225° or 5π/4

sin x=sin (180+45)=-sin 45≈-0.707

when x=240° or 4π/3

sin 240=sin (180+60)=-sin 60≈ -0.866

when x=270° or 3π/2

sin 270=sin (180+90)=-sin 90=-1

when x=300° or  5π/3

sin 300=sin(360-60)=-sin 60≈ -0.866

when x=315°or 7π/4

sin 315=sin (360-45)= -sin 45≈ -0.707

when x=330° or 13π/6

sin 330=sin (360-30)= -sin 30 =-0.5

when x=360 or 2π

sin (360)=sin (360+0)=sin 0=0

plot all these points on the graph,you get the reqd. graph.

you see it starts on (0,0)