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horrorfan [7]
3 years ago
13

How do I solve this by elimination {5x+y=0 5x+2y=30

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0
\left \{ {{5x+y=0\ \ | *(-2)} \atop {5x+2y=30}} \right. \\\\  \left \{ {{-10x-2y=0} \atop {5x+2y=30}} \right. \\+-----\\Elimination\ method\\\\
5x=30\ \ | divide\ by \ 5\\\\
x=6\\\\y=-5x=-5*6=-30\\\\Solution:\\ \left \{ {{y=-30} \atop {x=6}} \right.
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3 0
3 years ago
Read 2 more answers
19, find the direction angle of vector v to the nearest tenth of a degree
labwork [276]
The vector v is given by:
 v = (7, 2) - (-5, 0)
 v = ((7 - (- 5)), (2-0))
 v = ((7 + 5), 2)
 v = (12, 2)
 Then, the angle is given by:
 tan (theta) = 2/12
 theta = atan (2/12)
 theta = 9.46 degrees
 Answer:
 
The direction angle of vector to the nearest tenth of a degree is:
 
theta = 9.5 degrees
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