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aleksandr82 [10.1K]
3 years ago
11

if 1/2 an apple was shared equally among 3 people. what fracton of the who apple did each person recive.

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Answer:

1/6

Step-by-step explanation:

1/2/3 is a sixth of an apple that all 3 people equally shared.

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Answer:

<em>La cantidad de litros que ocupa dicho líquido es:</em>

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Step-by-step explanation:

<em>El volumen de un líquido puede obtenerse al tener tanto su densidad como su masa usando la siguiente fórmula:</em>

  • <em>Densidad = masa / volumen</em>

<em>Al despejar volumen se obtiene:</em>

  • <em>Volumen = masa / densidad </em>

<em>Por lo cual, si se reemplazara la fórmula quedaría:</em>

  • <em>Volumen = 7 Lb / 1.5 gr/cm^3</em>

<em>Sin embargo, </em><u><em>para operar, las unidades en las que se expresa la masa deben coincidir con las unidades de la densidad</em></u><em>, por lo cual vamos a convertir las libras en gramos teniendo en cuenta el siguiente factor de conversión:</em>

<em>1 libra = 453,592 gramos</em>

<em>Entonces:</em>

<em>7 lb =  453,592 gr * 7 = 3175,144 gr</em>

<em>Ahora este valor reemplaza la masa en la fórmula y calculamos:</em>

  • <em>Volumen del líquido =  3175,144 gr / 1.5 gr/cm^3</em>
  • <u><em>Volumen del líquido = 2116,762667 cm^3</em></u><em> (He utilizado todos los decimales para obtener el resultado exacto).</em>

<em>A simple vista ya se tiene el volumen del líquido en cuestión, sin embargo, el ejercicio pide que sea expresado en litros, por lo cual vamos a convertir los centímetros cúbicos en litros teniendo en cuenta el siguiente factor de conversión:</em>

<em>1 litro = 1000 centímetros cúbicos.</em>

<em>Ahora podemos aplicar una regla de tres simple, si:</em>

  • <em>1000 cm^3 = 1 L</em>
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<em>Y operamos:</em>

  • <em>x = (2116,762667 cm^3 * 1 L) / 1000 cm^3</em>
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<em>O si quieres un valor aproximado:</em>

  • <u><em>x = 2,12 Litros.</em></u>

<em>Entonces, la cantidad de litros teniendo en cuenta la densidad y la masa brindadas es </em><u><em>2,12 litros</em></u><em>.</em>

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