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3 years ago

How do you think inequalities are different from equations you have worked with before?

Mathematics

1 answer:

dmitriy555 [2]3 years ago

4 0

Answer:

Inequalities are different from equations. If you multiply or divide both sides of an equation by the same negative number, the equation remains the same, but If you multiply or divide both sides of an inequality by the same negative number, the inequality reverses.

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What is a ordered pair of numbers that identify a point on a coordinate plane

Paraphin [41]

Answer:A point is named by its ordered pair of the form of (x, y). The first number corresponds to the x-coordinate and the second to the y-coordinate. To graph a point, you draw a dot at the coordinates that corresponds to the ordered pair.

I HOPE IT HELPS :D

6 0

2 years ago

URGENT PLEASE HELP!!!20 POINTS!!!

VashaNatasha [74]

Add them all together and multiply by 2

3 0

3 years ago

Read 2 more answers

HELP FAST GIVE A DECENT AMOUNT OF POINTS! FOR EASY!

laila [671]

Answer:

The value of angle is 56.9°

Step-by-step explanation:

First, you have to find the length of hypotenuse using Pythagoras' Theorem, c² = a² + b² :

${c}^{2} = {a}^{2} + {b}^{2}$

$let \: a = 8.25 \\ let \: b = 6.45$

${c}^{2} = {8.25}^{2} + {6.45}^{2}$

${c}^{2} = 68.0625 + 41.6025$

${c}^{2} = 109.665$

$c = \sqrt{109.665}$

$c = 10.47cm \: (4s.f)$

In order to find θ, you have to apply Sine Rule :

$\sin(θ) = \frac{opposite}{adjacent}$

$let \: oppo. = 8.77 \\ let \: hypo. = 10.47$

$\sin(θ) = \frac{8.77}{10.47}$

$θ = { \sin( \frac{8.77}{10.47} ) }^{ - 1}$

$θ = 56.9 \: (1d.p)$

4 0

3 years ago

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks. Two students in t

melomori [17]

Answer:

The system of equation used to find the Total number of flash cards made are $\left \{ {{5x+5} \atop {6x}} \right.$ .

In 5 minutes, each student will have 30 flash cards.

Step-by-step explanation:

Given:

Number of flash cards already made by Tristan = 5

Number of flash card Tristan makes in 1 min = 5

Number of flash card Josh makes in 1 min = 6

We need to find the How long will Josh have same number of flashcards.

Also We need to find how many flashcards will each student have at that point.

Solution:

Let the number of minutes be $'x'$ .

Now we can say that;

Total number of flash cards made by Tristan is equal to Number of flash cards already made by Tristan plus Number of flash card Tristan makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Tristan = $5+5x$

Also We can say that;

Total number of flash cards made by Josh is equal Number of flash card Josh makes in 1 min multiplied by number of minutes.

framing in equation form we get;

Total number of flash cards made by Josh = $6x$

Hence the system of equation used to find the Total number of flash cards made are $\left \{ {{5x+5} \atop {6x}} \right.$ .

Now to find the number of minutes when both would have same number of flash cards we will make both the equation equal.

so we get;

$5+5x=6x$

On solving we get;

Combining like terms we get;

$6x-5x=5\\\\x=5\ mins$

Hence It would take 5 minutes when both will have same number of flash cards.

To find the number of flash cards each would had at that time we will substitute value of $x=5$ in the system of equations.

so we get;

number of flash cards made by Tristan = $5x+5 = 5\times5+5=25+5=30$

number of flash cards made by Josh = $6x =6\times 5 =30$

Hence In 5 minutes, each student will have 30 flash cards.

6 0

3 years ago

The map of a walking trail is drawn on a coordinate grid with three points of interest.

rewona [7]

Answer:

12 units

Step-by-step explanation:

Given the points :

R(−3, 2) - - - > S(2, 2) - - - - > T(2, −5).

Distance between R and S

Distance between two points is obtained thus :

D = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Distance between R and S

x1 = - 3 ; y1= 2 ; x2 = 2 ; y2 = 2

D1 = sqrt((2 - (-3))^2 + (2 - 2)^2)

D1 = sqrt((5^2 + 0^2))

D1 = sqrt(25)

D1 = 5

Distance between S and T

x1 = 2 ; y1= 2 ; x2 = 2 ; y2 = - 5

D2 = sqrt((2 - 2)^2 + (-5 - 2)^2)

D2 = sqrt((0^2 + (-7)^2))

D2 = sqrt(49)

D2 = 7

Hence, total length = D1 + D2 = 5 + 7 = 12 units

6 0

2 years ago