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AlexFokin [52]
3 years ago
6

How do you think inequalities are different from equations you have worked with before?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

Inequalities are different from equations.  If you multiply or divide both sides of an equation by the same negative number, the equation remains the same, but If you multiply or divide both sides of an inequality by the same negative number, the inequality reverses.

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Which value for x makes the sentence true?
marshall27 [118]

43/76

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The sum of the present ages of the mother and her daughter is 80 years. The mother was thrice as old as her daughter when she wa
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Answer:

let the daughter age be x

let mother age be 3x

Step-by-step explanation:

x+3x= 80

4x = 80

x= 80\4

x=20

daughter age is 20

mather age= 80 -20

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mother age 60

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Charles needs construction paper to finish a project. To wrap the box he knows he needs a lot of construction paper. The box is
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An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the
MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}=  1.45

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}=  3.59

6 0
3 years ago
Use the quadratic formula to solve x^2-6x=-7. Show your work. Then describe the solution.
s2008m [1.1K]

Answer: The solutions are x = 3+sqrt(2), and x = 3-sqrt(2). The quadratic equation has two solutions because it has a positive discriminant.

Step-by-step explanation:

Using the quadratic formula, we have: 6+-sqrt(8)/2, which become 3+-sqrt(2).

5 0
2 years ago
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