<span>11<span>5b</span></span>=<span><span><span>12</span></span></span><span><span><span>(11)</span>*<span>(2)</span></span>=<span>1*<span>5b</span></span></span><span>22=<span>5b</span></span>Step 2: Flip the equation.<span><span>5b</span>=22</span>Step 3: Divide both sides by 5.<span><span><span><span><span>5b</span>5</span></span></span>=<span><span><span>225</span></span></span></span><span>b=<span><span>22<span>5</span></span></span></span>
Answer:
every number you can think of
Step-by-step explanation:
6x - 3y = -6
=> 3(2x - y) = -6
=> 2x - y = -2
And you see there's a problem here. The question doesn't have enough information because x and y can be every numbers.
Take an example, x can be 200 and y can be 402 or x can be 5 and y can be 12.
Rewrite or check the question again so I can solve this :)
Answer:
f(x) = x² +x -6
Step-by-step explanation:
The standard form will look like ...
f(x) = x² +bx +c
where b is the opposite of the sum of the roots, and c is their product.
f(x) = x² -(-3+2)x +(-3)(2)
f(x) = x² +x -6
_____
<em>Additional comment</em>
In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).
We have been provided a diagram which tells us that Patti drew vertical line segments from two points to the line in her scatter plot. The first point she selected was dwarf crocodile. The second point she selected was for an Indian Gharial crocodile.
We can see that dwarf crocodile's bite force is closer to line of best fit than Indian Gharial crocodile. Indian Gharial crocodile seems to be an outlier for our data set.
Therefore, Patti's line have resulted in a predicted bite force that was closer to actual bite force for the dwarf crocodile.
Let's think about this. MQ is given to be a length of 24 units, PR a length of 10 whilst we must determine what length PM must be in order to satisfy the criteria of parallelogram MPQR to be a rhombus.
Assume this figure is a rhombus, rhombus MPQR. If that is so, all sides must be congruent, and the diagonals must be perpendicular ( ⊥ ) by " Properties of a Rhombus. " That would make triangle( s ) MRQ and say RMP isosceles, and by the Coincidence Theorem, MS ≅ QS, and RS ≅ PS. Therefore -
![MS = 1 / 2( 24 ) = 12 = QS,\\RS = 1 / 2( 10 ) = 5 = PS](https://tex.z-dn.net/?f=MS%20%3D%201%20%2F%202%28%2024%20%29%20%3D%2012%20%3D%20QS%2C%5C%5CRS%20%3D%201%20%2F%202%28%2010%20%29%20%3D%205%20%3D%20PS)
PS and MS are legs of a right triangle, so by Pythagorean Theorem we can determine the hypotenuse, or in other words the length of PM. This length would make parallelogram MPQR a rhombus,
![( PM )^2 = ( MS )^2 + ( PS )^2,\\PM^2 = ( 12 )^2 + ( 5 )^2,\\PM^2 = 144 + 25 = 169\\-----\\PM = 13](https://tex.z-dn.net/?f=%28%20PM%20%29%5E2%20%3D%20%28%20MS%20%29%5E2%20%2B%20%28%20PS%20%29%5E2%2C%5C%5CPM%5E2%20%3D%20%28%2012%20%29%5E2%20%2B%20%28%205%20%29%5E2%2C%5C%5CPM%5E2%20%3D%20144%20%2B%2025%20%3D%20169%5C%5C-----%5C%5CPM%20%3D%2013)
<u><em>And thus, PM should be 13 in length to make parallelogram MPQR a rhombus.</em></u>