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SIZIF [17.4K]
2 years ago
14

Please someone solve this, this is my third time reposting this question so yea please be quick

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

Step-by-step explanation:

to calculate mean add all the entries in a week ,then divide by 7(the number of days)

i give you hint

mean for week 1=(52+65+...   +60)/7

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30g of sugar is used to make 4 cakes. How much sugar is used to make 7 cakes
tankabanditka [31]

Answer:

52.5

Step-by-step explanation:

well first you want to find the ratio and to do that just do 30 / 4 which is

7.5 so for every 1 cake you need 7.5 grams of sugar

if you plug in 7 it is just 7 * 7.5

7 * 7.5 = 52.5

so it takes 52.5 grams of sugar to make 7 cakes

hope this helps please make brainliest

4 0
3 years ago
Read 2 more answers
Heather is making a blanket for her baby and is going to put a ribbon border around it. The blanket will be 3 feet by 5 feet. Th
mote1985 [20]

Answer:

The approximate total cost for the blanket is $10.08 ⇒ B

Step-by-step explanation:

The formula of the area of a rectangle is A = L × W

The formula of the perimeter of a rectangle is P = 2(L + W)

where:

  • L is the length of the rectangle
  • W is the width of the rectangle

∵ The baby blanket shaped a rectangle

∵ The dimensions of the blanket are 3 feet and 5 feet

- Find the area of the blanket

∵ A = 3 × 5 = 15 feet²

- Change feet to yard because the cost is by square yard

∵ 1 foot = \frac{1}{3} yard

∴ 1 foot² = (\frac{1}{3})^{2}=\frac{1}{9} yard²

∴ 15 feet² = 15 × (\frac{1}{9}) = \frac{5}{3} yards²

∴ The area of the blanket is  \frac{5}{3} yards²

∵ The fabric cost of the blanket is $1.25 per square yard

∴ The fabric cost =  \frac{5}{3} × 1.25

∴ The fabric cost = 2.08333 dollars

∵ Heather is going to put a ribbon border around it

- The length of the ribbon is equal to the perimeter of the blanket

∵ P = 2(3 + 5) = 16 feet

∴ The length of the ribbon is 16 feet

∵ The cost of the ribbon is $0.5 per foot

∴ The cost of the ribbon = 16 × 0.5

∴ The cost of the ribbon = 8 dollars

Now add the fabric cost to the ribbon cost to find the total cost of the blanket

∵ The total cost = 2.08333 + 8

∴ The total cost = 10.08333

- Round it to the nearest cent

∴ The total cost = 10.08 dollars

The approximate total cost for the blanket is $10.08

7 0
3 years ago
When dropped, a super ball will bounce back to 80% of its peak height,continuing on in this way for each bounce.
Liono4ka [1.6K]

An expression for the height of the nth bounce is 0.80X^N = Height.

<h3><u>Equations</u></h3>

Since when dropped, a super ball will bounce back to 80% of its peak height, continuing on in this way for each bounce, to determine an expression for the height of the nth bounce the following calculation must be performed:

  • X = Initial value
  • 80% = 0.80
  • N = Number of times the ball bounces
  • 0.80X^N = Height

Therefore, an expression for the height of the nth bounce is 0.80X^N = Height.

Learn more about equations in brainly.com/question/2263981

3 0
2 years ago
Of the total number of spectators at a circus show, 1/4 are men. 2/5 of the remaining number of spectators are women. There are
ch4aika [34]

Answer: There are 198 children at the circus show.

Step-by-step explanation:

Let be "x" the total number of spectators at the circus show and "c" the number of children at the circus show.

Knowing that \frac{1}{4} of the spectators are men, we can find the remaining:

x-\frac{1}{4}x=\frac{3}{4}x

Since \frac{2}{5} of the remaining number of spectaros are women and there are a total of 132 women, we can write the following equation:

(\frac{2}{5})(\frac{3}{4}x)=132

Solving for "x", we get:

x=(132)(\frac{20}{6})\\\\x=440

Therefore, we get that "c" is:

 c=440-\frac{1}{4}(440)-132\\\\c=198

8 0
3 years ago
A rectangular storage container with an open top is to have a volume of 24 cubic meters. The length of its base is twice the wid
Mariana [72]

Answer:

419.25

Step-by-step explanation:

The calculation of the cost of materials for the cheapest such container is shown below:-

We assume

Width = x

Length = 2x

Height = h

where, length = 2 \times width

Base area = lb

= 2x^2

Side area = 2lh + 2bh

= 2(2x)h + 2(x)h

= 4xh + 2xh

Volume = 24 which is lbh = 24

h = \frac{24}{2x^2} \\\\ h = \frac{12}{x^2}

Now, cost is

= 13(2x^2) + 9(4xh + 2xh)\\\\ = 13(2x^2) + 9(4x + 2x)\times \frac{12}{x^2} \\\\ = 26x^2 + \frac{648}{x}

now we have to minimize C(x)

So, we need to compute the C'(x)

= 52x - \frac{648}{x^2}

C"(x)  = 52x - \frac{1,296}{x^3}

now for the critical points, we will solve the equation C'(x) = 0

= 52x - \frac{648}{x^2} = 0\\\\ x = \frac{648}{52}^{\frac{1}{3}}

C" = ((\frac{648}{52} ^{\frac{1}{3} } = 52 + \frac{1296}{(\frac{648}{52})^\frac{1}{3} )^3}\\\\ = 52 + \frac{1296}{\frac{648}{52} } >0

So, x is a point of minima that is

= (\frac{648}{52} )^\frac{1}{3}

Now, Base material cost is

= 13(2x^2)\\\\ = 26(\frac{648}{52} )^\frac{2}{3}

= 139.75

Side material cost is

= \frac{648}{x} \\\\ = \frac{648}{(\frac{648}{52})^\frac{1}{3}  }

= 279.50

and finally

Total cost is

= 139.75 + 279.50

= 419.25

4 0
3 years ago
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