The first one is d I believe and The second is B and C
I dont know the rest
<span>3(2y - 4) = 8y + 9 - 9y
Distribute 3:
6y - 12 = 8y + 9 - 9y
Combine like terms:
6y - 12 = -y + 9
Add y to both sides:
7y - 12 = 9
Add 12 to both sides:
7y = 21
Divide both sides by 3:
y = 3</span>
Answer:
![P(x\geq 2)=0.9753](https://tex.z-dn.net/?f=P%28x%5Cgeq%202%29%3D0.9753)
Step-by-step explanation:
The number of adults that use smartphones in meetings or classes follows a binomial distribution. So, the probability that x adults use their smartphones in meetings or classes is calculated as:
![P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28x%29%3D%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D%2Ap%5Ex%2A%281-p%29%5E%7Bn-x%7D)
Where, n is the number of identical and independents events, in this case, 7 adults with smartphones. p is the probability of success or the probability that the adult use the smartphone in meeting or classes, in this case, p is equal to 0.58
So, replacing values, we get that the probability that x adults use their smartphones in meetings or classes is:
![P(x)=\frac{7!}{x!(7-x)!}*0.58^x*(1-0.58)^{7-x}](https://tex.z-dn.net/?f=P%28x%29%3D%5Cfrac%7B7%21%7D%7Bx%21%287-x%29%21%7D%2A0.58%5Ex%2A%281-0.58%29%5E%7B7-x%7D)
Now, the probability that at least 2 of them use their smartphones in meetings or classes is calculated as:
![P(x\geq 2)=P(2)+P(3)+P(4)+P(5)+P(6)+P(7)](https://tex.z-dn.net/?f=P%28x%5Cgeq%202%29%3DP%282%29%2BP%283%29%2BP%284%29%2BP%285%29%2BP%286%29%2BP%287%29)
Where:
![P(2)=\frac{7!}{2!(7-2)!}*0.58^2*(1-0.58)^{7-2}=0.0923\\P(3)=\frac{7!}{3!(7-3)!}*0.58^3*(1-0.58)^{7-3}=0.2125\\P(4)=\frac{7!}{4!(7-4)!}*0.58^4*(1-0.58)^{7-4}=0.2934\\P(5)=\frac{7!}{5!(7-5)!}*0.58^5*(1-0.58)^{7-5}=0.2431\\P(6)=\frac{7!}{6!(7-6)!}*0.58^6*(1-0.58)^{7-6}=0.1119\\P(7)=\frac{7!}{7!(7-7)!}*0.58^7*(1-0.58)^{7-7}=0.0221](https://tex.z-dn.net/?f=P%282%29%3D%5Cfrac%7B7%21%7D%7B2%21%287-2%29%21%7D%2A0.58%5E2%2A%281-0.58%29%5E%7B7-2%7D%3D0.0923%5C%5CP%283%29%3D%5Cfrac%7B7%21%7D%7B3%21%287-3%29%21%7D%2A0.58%5E3%2A%281-0.58%29%5E%7B7-3%7D%3D0.2125%5C%5CP%284%29%3D%5Cfrac%7B7%21%7D%7B4%21%287-4%29%21%7D%2A0.58%5E4%2A%281-0.58%29%5E%7B7-4%7D%3D0.2934%5C%5CP%285%29%3D%5Cfrac%7B7%21%7D%7B5%21%287-5%29%21%7D%2A0.58%5E5%2A%281-0.58%29%5E%7B7-5%7D%3D0.2431%5C%5CP%286%29%3D%5Cfrac%7B7%21%7D%7B6%21%287-6%29%21%7D%2A0.58%5E6%2A%281-0.58%29%5E%7B7-6%7D%3D0.1119%5C%5CP%287%29%3D%5Cfrac%7B7%21%7D%7B7%21%287-7%29%21%7D%2A0.58%5E7%2A%281-0.58%29%5E%7B7-7%7D%3D0.0221)
Finally,
is equal to:
![P(x\geq 2)=0.0923+0.2125+0.2934+0.2431+0.1119+0.0221\\P(x\geq 2)=0.9753](https://tex.z-dn.net/?f=P%28x%5Cgeq%202%29%3D0.0923%2B0.2125%2B0.2934%2B0.2431%2B0.1119%2B0.0221%5C%5CP%28x%5Cgeq%202%29%3D0.9753)
The answer is D -1/2
As the equation relates to that answerr
The correct answer is x>-2. The graph is attached.
To solve this:
-x/2 + 3/2 < 5/2
Subtract 3/2 from both sides:
-x/2 + 3/2 - 3/2 < 5/2 - 3/2
-x/2 < 2/2
-x/2 < 1
Multiply both sides by 2:
(-x/2)*2 < 1*2
-x < 2
Divide both sides by -1:
-x/-1 < 2/-1
Remember to flip the the symbol since you divide both sides by a negative:
x > -2
To graph the inequality, we draw a number line, making sure we have -2 on it. We circle -2 and leave it open, since it is strictly greater than. Then we shade the line to the left.