15/5 is 3
So then you change the equation to be 12=15z-3 ( don’t forgot the negative sign)
Move the constant to the right side and change the sign
-15z= -3 -12
-3-12 is -15
Divide -15z= -15
Your final answer will be z= 1
The given operation involves just swapping the two rows, so carrying out
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)
Answer:
8
Step-by-step explanation:
if we take the 2 that is in the R.H.S and put it in L.H.S
it becomes 16÷2=8
Answer:
A,C,F
Step-by-step explanation:
Answer:ur mising 346789
Step-by-step explanation:
